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2. c++ - Return array in a function - Stack Overflow

   stackoverflow.com/questions/3473438

   C++ functions can't return C-style arrays by value. The closest thing is to return a pointer. Furthermore, an array type in the argument list is simply converted to a pointer. int *fillarr( int arr[] ) { // arr "decays" to type int * return arr; }

3. C++ Array of Functions - Stack Overflow

   stackoverflow.com/questions/16329087

   You can declare them as follow: int AlarmEvent1() {return 1}; int AlarmEvent2() {return 1}; int AlarmEvent3() {return 1}; int AlarmEvent4() {return 1}; //So on. This way, you can add them to your array and use them. I haven't tried to compile it yet, but it should work or at least the direction for you is there.

4. Passing Arrays to Function in C++ - Stack Overflow

   stackoverflow.com/questions/14309136

   10. firstarray and secondarray are converted to a pointer to int, when passed to printarray(). printarray(int arg[], ...) is equivalent to printarray(int *arg, ...) However, this is not specific to C++. C has the same rules for passing array names to a function. answered Jan 13, 2013 at 22:51.

5. Altering an array from a function in C++ - Stack Overflow

   stackoverflow.com/questions/13295011

   In order to make the original x in someFunction4() hold the values you assigned, do one of two things: 1) Get rid of x = new int[n];. This will make someFunction4() work like the previous ones. 2) Pass a pointer to x as an argument to someFunction4() and have someFunction4() take a pointer. int someFunction4(int *x[], int n) {. *x = new int[n];

6. c++ - How define an array of function pointers in C - Stack...

   stackoverflow.com/questions/5488608

   int (*foo_ptr_array[2])( int ) declares a variable called foo_ptr_array which is an array of 2 function pointers. The syntax can get pretty messy, so it's often easier to make a typedef to the function pointer and then declare an array of those instead: typedef int (*foo_ptr_t)( int ); foo_ptr_t foo_ptr_array[2];

7. Passing a 2D array to a C++ function - Stack Overflow

   stackoverflow.com/questions/8767166

   Jan 9, 2019 at 4:24. Future reference: In short you can't pass variable sized 2d arrays int arr [m] [n] to functions in c/cpp easily. work around is pass &arr [0] [0] into a function func (int arr) then do arr [in+j] to access arr [i] [j] within func. Or you can pass define int **arr using new/malloc in cpp/c.

8. c++ - How to declare an array of functions? - Stack Overflow

   stackoverflow.com/questions/68814264

   4. Strictly speaking you may not declare an array of functions. You may declare an array of function pointers. It seems you mean. int (*funcs[10])(int, int); Another way is to introduce a using declaration (or a typedef declaration) like for example. using FP = int( * )( int, int ); FP funcs[10]; or.

9. c++ - Passing an array by reference - Stack Overflow

   stackoverflow.com/questions/5724171

   It's a syntax for array references - you need to use (&array) to clarify to the compiler that you want a reference to an array, rather than the (invalid) array of references int & array[100];. EDIT: Some clarification. void foo(int * x); void foo(int x[100]); void foo(int x[]); These three are different ways of declaring the same function.

10. c++ - How to return an array from a function? - Stack Overflow

    stackoverflow.com/questions/4264304

    It is not possible to return an array from a C++ function. 8.3.5[dcl.fct]/6: Functions shall not have a return type of type array or function[...] Most commonly chosen alternatives are to return a value of class type where that class contains an array, e.g. struct ArrayHolder { int array[10]; }; ArrayHolder test();

11. c - How can I use an array of function pointers? - Stack Overflow

    stackoverflow.com/questions/252748

    All functions stored in the array must have the same signature. This simply means that they must return the same type (e.g. int ) and have the same arguments (a single int in the example above). In C++, you can do the same with static class methods (but not instance methods).