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Hydrogen iodide (HI) is a diatomic molecule and hydrogen halide. Aqueous solutions of HI are known as hydroiodic acid or hydriodic acid, a strong acid . Hydrogen iodide and hydroiodic acid are, however, different in that the former is a gas under standard conditions, whereas the other is an aqueous solution of the gas .
Hydrogen iodide. The simplest compound of iodine is hydrogen iodide, HI.It is a colourless gas that reacts with oxygen to give water and iodine. Although it is useful in iodination reactions in the laboratory, it does not have large-scale industrial uses, unlike the other hydrogen halides.
It is an aqueous solution of hydrogen iodide with the chemical formula H I. It is a strong acid, in which hydrogen iodide is ionized completely in an aqueous solution. Concentrated aqueous solutions of hydrogen iodide are usually 48% to 57% HI by mass. [2] An oxidized solution of hydriodic acid.
Aqueous hydrogen iodide is known as hydroiodic acid, which is a strong acid. Hydrogen iodide is exceptionally soluble in water: one litre of water will dissolve 425 litres of hydrogen iodide, and the saturated solution has only four water molecules per molecule of hydrogen iodide. [49]
The following chart shows the solubility of various ionic compounds in water at 1 atm pressure and room temperature (approx. 25 °C, 298.15 K). "Soluble" means the ionic compound doesn't precipitate, while "slightly soluble" and "insoluble" mean that a solid will precipitate; "slightly soluble" compounds like calcium sulfate may require heat to precipitate.
The Bunsen reaction is a chemical reaction that describes water, sulfur dioxide, and iodine reacting to form sulfuric acid and hydrogen iodide: 2H 2 O + SO 2 + I 2 → H 2 SO 4 + 2HI. This reaction is the first step in the sulfur-iodine cycle to produce hydrogen.
In this protocol, iodide ion is generated by the following slow reaction between the iodate and bisulfite: IO − 3 + 3 HSO − 3 → I − + 3 HSO − 4. This first step is the rate determining step. Next, the iodate in excess will oxidize the iodide generated above to form iodine: IO − 3 + 5 I − + 6 H + → 3 I 2 + 3 H 2 O
The low solubility of silver iodide and lead iodide reflects the covalent character of these metal iodides. A test for the presence of iodide ions is the formation of yellow precipitates of these compounds upon treatment of a solution of silver nitrate or lead(II) nitrate. [2] Aqueous solutions of iodide salts dissolve iodine better than pure ...