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The hypothetical effect of a bound diproton on Big Bang and stellar nucleosynthesis, has been investigated. [18] Some models suggest that variations in the strong force allowing a bound diproton would enable the conversion of all primordial hydrogen to helium in the Big Bang, which would be catastrophic for the development of stars and life.
If the nucleus is assumed to be spherically symmetric, an approximate relationship between nuclear radius and mass number arises above A=40 from the formula R=R o A 1/3 with R o = 1.2 ± 0.2 fm. [6] R is the predicted spherical nuclear radius, A is the mass number, and R o is a constant determined by experimental data.
It is the reaction which occurs when a neutron enters a nucleus and a proton leaves the nucleus simultaneously. [1] For example, sulfur-32 (32 S) undergoes an (n,p) nuclear reaction when bombarded with neutrons, thus forming phosphorus-32 (32 P). The nuclide nitrogen-14 (14 N) can also undergo an (n,p) nuclear reaction to produce carbon-14 (14 C).
One consequence of these complications is that although deuterium, a bound state of a proton (p) and a neutron (n) is stable, exotic nuclides such as diproton or dineutron are unbound. [11] The nuclear force is not sufficiently strong to form either p-p or n-n bound states, or equivalently, the nuclear force does not form a potential well deep ...
Comparison between the Nuclear Force and the Coulomb Force. a – residual strong force (nuclear force), rapidly decreases to insignificance at distances beyond about 2.5 fm, b – at distances less than ~ 0.7 fm between nucleons centres the nuclear force becomes repulsive, c – coulomb repulsion force between two protons (over 3 fm, force becomes the main), d – equilibrium position for ...
Diproton fusion into helium-4, lithium-4, helium-3 and a proton, and such could proceed much as regular fusion does. Elements with high masses would be more stable, and low neutron numbers would be favored relative to now, because of the neutron's higher mass.
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In both cases, this causes the diproton and dineutron to be unstable. The proton and neutron in deuterium can be dissociated through neutral current interactions with neutrinos. The cross section for this interaction is comparatively large, and deuterium was successfully used as a neutrino target in the Sudbury Neutrino Observatory experiment.