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22. In a nutshell, lazy evaluation means that the object is evaluated when it is needed, not when it is created. In Python 2, range will return a list - this means that if you give it a large number, it will calculate the range and return at the time of creation: >>> i = range(100) >>> type(i) <type 'list'>.
The function evaluation requires all threads to run. I am not able to check any variable anymore. I am not explicitly working with threads. What can I do to get it working again? I already disabled, as mentioned in some forums, the function: "Enable property Evaluation and other implicit function Calls" in the option window of the debugger.
Update: Thanks! Two questions: (1) if function test further takes an argument for f, will you add something like test <- function(g.=g, T=1, f..=f){ g.(1,T, f.=f..)
2. Short-circuit, or minimal evaluation is just syntactic sugar for nested ifs. To assume it is inefficient, or causes stalls is a case of premature optimization. At this point, most compilers are intelligent enough to correctly interpret and optimize these statements.
The output is attempting to help you to understand how the changes you are making to your application are affecting its auto-configuration. You can turn off the logging of the delta if you wish. To do so, set the following property: spring.devtools.restart.log-condition-evaluation-delta=false. answered Jul 15, 2019 at 8:43.
The order of evaluation of the function designator, the actual arguments, and subexpressions within the actual arguments is unspecified, but there is a sequence point before the actual call. This program also exhibits undefined behavior since you are modifying pa more than once between sequence points. From draft standard section 6.5 paragraph 2:
In any case proceed. 3. Go to the Gradle option on right side of the studio (look at the right edge) press it, click on main-project, you will see your project-lib option, click it, then ->Tasks->Build->Assemble Debug and Assemble Release.
The evaluation takes place only when the final result is assigned to a matrix instance. EDIT I should have been more explicit. As it is, the code makes no sense because although evaluation happens lazily, it still happens in the same expression.
Short-circuiting the evaluation of an expression means that only a part of the expression needs to be evaluated before finding its value. For example: a == null || a.size() == 0 If a is null, the a.size() == 0 subexpression won't be evaluated, because the boolean operator || evaluates to true if one of its operands is true. Similarly, for this ...
assert train_size + val_size + test_size == 1, "Train, validation, and test sizes must add up to 1." # Split the dataframe into training and test sets. train_df, test_df = train_test_split(df, test_size=test_size, random_state=random_state) # Calculate the size of the validation set relative to the original dataframe.