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Sodium bicarbonate (IUPAC name: sodium hydrogencarbonate [9]), commonly known as baking soda or bicarbonate of soda, is a chemical compound with the formula NaHCO 3. It is a salt composed of a sodium cation (Na +) and a bicarbonate anion (HCO 3 −). Sodium bicarbonate is a white solid that is crystalline but often appears as a fine powder.
Note that the especially high molar values, as for paraffin, gasoline, water and ammonia, result from calculating specific heats in terms of moles of molecules. If specific heat is expressed per mole of atoms for these substances, none of the constant-volume values exceed, to any large extent, the theoretical Dulong–Petit limit of 25 J⋅mol ...
C 2 H 3 Na O 2: Molar mass: 82.034 g·mol −1 : Appearance White deliquescent powder or crystals Odor: Vinegar (acetic acid) odor when heated to decomposition [1]: Density: 1.528 g/cm 3 (20 °C, anhydrous)
Molecular weight (M.W.) (for molecular compounds) and formula weight (F.W.) (for non-molecular compounds), are older terms for what is now more correctly called the relative molar mass (M r). [8] This is a dimensionless quantity (i.e., a pure number, without units) equal to the molar mass divided by the molar mass constant .
Mass fraction can also be expressed, with a denominator of 100, as percentage by mass (in commercial contexts often called percentage by weight, abbreviated wt.% or % w/w; see mass versus weight). It is one way of expressing the composition of a mixture in a dimensionless size ; mole fraction (percentage by moles , mol%) and volume fraction ...
2 at constant volume is 20.6 J⋅K −1 ⋅mol −1 (at 15 °C, 1 atm), which is 2.49 R. [11] From the theoretical equation c V,m = 1 / 2 fR, one concludes that each molecule has f = 5 degrees of freedom. These turn out to be three degrees of the molecule's velocity vector, plus two degrees from its rotation about an axis through the ...
Historically, the mole was defined as the amount of substance in 12 grams of the carbon-12 isotope.As a consequence, the mass of one mole of a chemical compound, in grams, is numerically equal (for all practical purposes) to the mass of one molecule or formula unit of the compound, in daltons, and the molar mass of an isotope in grams per mole is approximately equal to the mass number ...
1/K 1 =1/ k 11 + 1/k 12, and therefore K 1 = k 11 k 12 / ( k 11 + k 12 ). Thus, in this example there are four micro-constants whose values are subject to two constraints; in consequence, only the two macro-constant values, for K 1 and K 2 can be derived from experimental data.