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A multiple of a number is the product of that number and an integer. For example, 10 is a multiple of 5 because 5 × 2 = 10, so 10 is divisible by 5 and 2. Because 10 is the smallest positive integer that is divisible by both 5 and 2, it is the least common multiple of 5 and 2.
The greatest common divisor (GCD) of integers a and b, at least one of which is nonzero, is the greatest positive integer d such that d is a divisor of both a and b; that is, there are integers e and f such that a = de and b = df, and d is the largest such integer.
Download as PDF; Printable version; In other projects Wikidata item; ... Greatest common divisor, also known as the greatest common factor; Least common multiple;
On the right Nicomachus's example with numbers 49 and 21 resulting in their GCD of 7 (derived from Heath 1908:300). In mathematics , the Euclidean algorithm , [ note 1 ] or Euclid's algorithm , is an efficient method for computing the greatest common divisor (GCD) of two integers , the largest number that divides them both without a remainder .
lcm(m, n) (least common multiple of m and n) is the product of all prime factors of m or n (with the largest multiplicity for m or n). gcd(m, n) × lcm(m, n) = m × n. Finding the prime factors is often harder than computing gcd and lcm using other algorithms which do not require known prime factorization.
Then the matrix () having the greatest common divisor (,) as its entry is referred to as the GCD matrix on .The LCM matrix [] is defined analogously. [ 1 ] [ 2 ] The study of GCD type matrices originates from Smith (1875) who evaluated the determinant of certain GCD and LCM matrices.
Equivalently, g(n) is the largest least common multiple (lcm) of any partition of n, or the maximum number of times a permutation of n elements can be recursively applied to itself before it returns to its starting sequence. For instance, 5 = 2 + 3 and lcm(2,3) = 6. No other partition of 5 yields a bigger lcm, so g(5) = 6.
For example, the addition of two rational numbers whose denominators are bounded by b leads to a rational number whose denominator is bounded by b 2, so in the worst case, the bit size could nearly double with just one operation. To expedite the computation, take a ring D for which f and g are in D[x], and take an ideal I such that D/I is a ...