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Shape of water molecule showing that the real bond angle 104.5° deviates from the ideal sp 3 angle of 109.5°. In chemistry, Bent's rule describes and explains the relationship between the orbital hybridization and the electronegativities of substituents. [1] [2] The rule was stated by Henry A. Bent as follows: [2]
In chemistry, molecules with a non-collinear arrangement of two adjacent bonds have bent molecular geometry, also known as angular or V-shaped. Certain atoms, such as oxygen, will almost always set their two (or more) covalent bonds in non-collinear directions due to their electron configuration. Water (H 2 O) is an example of a bent molecule ...
Another example is O(SiH 3) 2 with an Si–O–Si angle of 144.1°, which compares to the angles in Cl 2 O (110.9°), (CH 3) 2 O (111.7°), and N(CH 3) 3 (110.9°). [24] Gillespie and Robinson rationalize the Si–O–Si bond angle based on the observed ability of a ligand's lone pair to most greatly repel other electron pairs when the ligand ...
The bond angles in the table below are ideal angles from the simple VSEPR theory (pronounced "Vesper Theory") [citation needed], followed by the actual angle for the example given in the following column where this differs. For many cases, such as trigonal pyramidal and bent, the actual angle for the example differs from the ideal angle, and ...
Bent bonds are found in strained organic compounds such as cyclopropane, oxirane and aziridine. In these compounds, it is not possible for the carbon atoms to assume the 109.5° bond angles with standard sp 3 hybridization. Increasing the p-character to sp 5 (i.e. 1 ⁄ 6 s-density and 5 ⁄ 6 p-density) [5] makes it possible to reduce the bond ...
However, this prediction (120° bond angles) is inconsistent with the bond angle of H 2 O being 104.5°. The actual hybridization of H 2 O can be explained via the concept of isovalent hybridization or Bent's rule. In short, s character is accumulated in lone pair orbitals because s character is energy lowering relative to p character, and lone ...
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This would result in the geometry of a regular tetrahedron with each bond angle equal to arccos(− 1 / 3 ) ≈ 109.5°. However, the three hydrogen atoms are repelled by the electron lone pair in a way that the geometry is distorted to a trigonal pyramid (regular 3-sided pyramid) with bond angles of 107°.