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PV = nRT P V = n R T. or, expressing pressure as a function of volume, P(V) = nRT V P (V) = n R T V. meaning, for an ideal gas, the pressure varies inversely with volume if the temperature is constant (an isothermal process). It can not vary directly (linearly) with volume. But the problem statement does say " somehow " the helium is made to to ...
ΔK = W Δ K = W. The above theorem was derived directly from the second Newton's law of motion and from the definition of work. What it says is that change of kinetic energy equals total work done on an object. Since kinetic energy is defined as K = 12mv2 K = 1 2 m v 2 the above equation can also be written as.
The factor of $2$ or $1/2$ comes from integration. One watt is defined as one joule per second, the power needed to produce one joule of energy as quickly as in one second. So one watt is defined as ${\rm J}/{\rm s}$. One volt is defined as the voltage at which one ampere current has the power of one watt.
To prove how volts is related to energy transfer and charge you can do: E = VIt. V = E/It. V = J/Cs -1 x s. You can cancel out the seconds, leaving: J/C. Joules per coulomb is equal to volts. This is how we've been taught, but I don't understand why for current (Cs) it is to the power of -1.
As you already said One Joule is 1 Joule is 1 newton exerted through a distance of one meter. Joules measure how much energy you need to give to the system to move it from point A to point B. And, as you rightly said it is measured by W=F*d. So 490J 490 J is 490N 490 N over 1 metre as 490 ∗ 1 = 490 490 ∗ 1 = 490 also it is 1N 1 N over 490 ...
An electronvolt is just the energy acquired when an electron falls through a potential of 1 volt, which means. 1eV = e × 1V = 1.6 ×10−19 J 1 e V = e × 1 V = 1.6 × 10 − 19 J. When you lift your 2.5kg 2.5 k g laptop (a 15-inch Apple MacBook Pro, for example) by a foot, you do work of approximately 2.5kg × 10ms−2 × 0.3m = 7.5J 2.5 k g ...
Is 3.25kcal the same amount of energy as 3.25jouls? No, to convert from cal. to joules 1 cal. = 4.18400 joules , then 1KCal = (4.18400 *10^-3) joules so 3.25 kcal doesn't equal 3.25 Joules
The units for torque, as you stated, are Newton-meters. Although this is algebraically the same units as Joules, Joules are generally not appropriate units for torque. Why not? The simple answer is because. W = F ⋅d W = F → ⋅ d →. where W W is the work done, F F → is the force, d d → is the displacement, and ⋅ ⋅ indicates the ...
I know that the unit of kinetic energy is Joules, J. However, the book I have says that the "unit of kinetic energy is equivalent to $\text{Pa}\cdot\text{m}^3$. I have been trying to prove this result, which is also shown on wikipedia, but came to no result.
The same calculation would give around 3500 kg of coal equivalent to 1 gram of 100% U-235. That is close enough to the commonly quoted value. Of course the amount of heat given off by coal varies a lot with the type - sources vary by more than 2x between the lowest and highest energy density coal.