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15 feet is equal to 457.2 cm. Each feet has 12 inches and each inch is equivalent to 2.54 cm. Hence one feet is equal to 1xx12xx2.54 cm.. and 15 feet is equal to 15xx12xx2.54 cm. = 180xx2,54=457.2 cm.
168 cm are equal to approximately 5 feet and 6 inches. Each inch is equal to 2.54 cm. Therefor, each cm is equal to 1/2.54=0.3937 inches. Hence, 168 cm are equal to 168xx0.3937=66.1416 inches. As each feet has 12 inches, 5 feet are equal to 12xx5=60 inches and hence 168 cm are equal to 5 feet and 6.1416 inches or rounding it say 5 feet and 6 inches..
That is basically correct, except the cm value should be 79, not 80. This is a conversion that just depends on the accuracy of the standard. As a basis we can use 1.00 "inch" = 2.54cm, 1.00 "foot" = 12.0 "inches" and 1.00m = 100cm For the example, 9'2" can be converted first into inches: 9 xx 12 + 2 = 110"inches". This can be converted into cm: 110 xx 2.54 = 279.4cm This can then be converted ...
Andy is 6 feet tall. If l inch equals 2.54 centimeters, how tall is Andy to the nearest centimeter?
"400 cm" >>"1 m = 100 cm" "4 m" = 4 cancel"m" × "100 cm"/(1 cancel"m") = "400 cm" ∴ There are 400 centimetres in 4 metres.
12 xx2.54 = 30.48cm If 1 " inch" = 2.54 cm, "then 12 inches" = 12 xx 2.54 cm 12xx2.54 = 30.48 cm Or use direct proportion to compare cm to inches. 1/2.54 = 12/x" "(larr"inches")/(larr "cm") x = 12 xx2.54 = 30.48cm
From the circumference you can determine the radius. Once you have the radius, you calculate the area as pir^2 The answer will be A=201cm^2 If the circumference is 50.24, the radius must be r=50.24/(2pi), because the circumference is always equal to 2pir. So, r=50.24/(2pi) = 8.0 cm Since the area is A=pir^2, we obtain A=pi(8^2)= 201cm^2
6 × 2 For the rectangle Length= ℓ Breadth= b Area is 12\ "cm"^2 ℓb = 12 Perimeter is 16\ "cm" 2(ℓ + b)= 16 ℓ + b = 8 Substitute b = 12/ℓ from first equation ℓ + 12/ℓ = 8 ℓ^2 + 12 = 8 ℓ ℓ^2 - 8 ℓ + 12 = 0 Use quadratic formula (x = (-b +- sqrt(b^2 - 4ac))/(2a)) to find ℓ ℓ = (-(-8) +- sqrt((-8)^2 - (4 × 1 × 12)))/(2 × 1) ℓ = (8 +- sqrt(16))/2 ℓ = (8 +- 4)/2 ℓ ...
The volume of a cube is increasing at the rate of 20 cubic centimeters per second. How fast, in square centimeters per second, is the surface area of the cube increasing at the instant when each edge of the cube is 10 centimeters long?
1/(20pi) cm/s The first thing to do is to write out what we do know about the problem. We know the volume of the balloon is increasing at a rate of 10 cm^3/s This is expressed as: (dV)/dt=10 The volume of a sphere is given by: V=4/3pir^3 The question asks to find the rate of which the diameter is increasing when the diameter is 20. The formula gives volume in terms of the radius, not the ...