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  2. Molar volume - Wikipedia

    en.wikipedia.org/wiki/Molar_volume

    The ideal gas equation can be rearranged to give an expression for the molar volume of an ideal gas: = = Hence, for a given temperature and pressure, the molar volume is the same for all ideal gases and is based on the gas constant: R = 8.314 462 618 153 24 m 3 ⋅Pa⋅K −1 ⋅mol −1, or about 8.205 736 608 095 96 × 10 −5 m 3 ⋅atm⋅K ...

  3. Apparent molar property - Wikipedia

    en.wikipedia.org/wiki/Apparent_molar_property

    For instance, solid NaCl has a volume of 27 cm 3 per mole, but the apparent molar volume at low concentrations is only 16.6 cc/mole. In fact, some aqueous electrolytes have negative apparent molar volumes: NaOH −6.7, LiOH −6.0, and Na 2 CO 3 −6.7 cm 3 /mole. [ 4 ]

  4. Specific volume - Wikipedia

    en.wikipedia.org/wiki/Specific_volume

    For a substance X with a specific volume of 0.657 cm 3 /g and a substance Y with a specific volume 0.374 cm 3 /g, the density of each substance can be found by taking the inverse of the specific volume; therefore, substance X has a density of 1.522 g/cm 3 and substance Y has a density of 2.673 g/cm 3. With this information, the specific ...

  5. Specific weight - Wikipedia

    en.wikipedia.org/wiki/Specific_weight

    The specific weight, also known as the unit weight (symbol γ, the Greek letter gamma), is a volume-specific quantity defined as the weight W divided by the volume V of a material: = / Equivalently, it may also be formulated as the product of density, ρ, and gravity acceleration, g: = Its unit of measurement in the International System of Units (SI) is newton per cubic metre (N/m 3), with ...

  6. Number density - Wikipedia

    en.wikipedia.org/wiki/Number_density

    Using the number density as a function of spatial coordinates, the total number of objects N in the entire volume V can be calculated as = (,,), where dV = dx dy dz is a volume element. If each object possesses the same mass m 0 , the total mass m of all the objects in the volume V can be expressed as m = ∭ V m 0 n ( x , y , z ) d V ...

  7. Van der Waals equation - Wikipedia

    en.wikipedia.org/wiki/Van_der_Waals_equation

    That is 8 times ⁠ ⁠, the volume of each particle of radius ⁠ / ⁠, but there are 2 particles which gives 4 times the volume per particle. The total excluded volume is then ⁠ = ⁠; that is, 4 times the volume of all the particles. Van der Waals and his contemporaries used an alternative, but equivalent, analysis based on the mean free ...