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Sodium amide can be prepared by the reaction of sodium with ammonia gas, [3] but it is usually prepared by the reaction in liquid ammonia using iron(III) nitrate as a catalyst. The reaction is fastest at the boiling point of the ammonia, c. −33 °C. An electride, [Na(NH 3) 6] + e −, is formed as a reaction intermediate. [4] 2 Na + 2 NH 3 ...
The Birch reduction is an organic reaction that is used to convert arenes to 1,4-cyclohexadienes.The reaction is named after the Australian chemist Arthur Birch and involves the organic reduction of aromatic rings in an amine solvent (traditionally liquid ammonia) with an alkali metal (traditionally sodium) and a proton source (traditionally an alcohol).
At 15.6 °C (60.1 °F), the density of a saturated solution is 0.88 g/ml; it contains 35.6% ammonia by mass, 308 grams of ammonia per litre of solution, and has a molarity of approximately 18 mol/L. At higher temperatures, the molarity of the saturated solution decreases and the density increases. [ 8 ]
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An electride is an ionic compound in which an electron serves the role of the anion. [1] Solutions of alkali metals in ammonia are electride salts. [2] In the case of sodium, these blue solutions consist of [Na(NH 3) 6] + and solvated electrons: Na + 6 NH 3 → [Na(NH 3) 6] + + e −. The cation [Na(NH 3) 6] + is an octahedral coordination ...
In chemistry, ammonolysis (/am·mo·nol·y·sis/) is the process of splitting ammonia into + +. [1] Ammonolysis reactions can be conducted with organic compounds to produce amines (molecules containing a nitrogen atom with a lone pair, :N), [2] or with inorganic compounds to produce nitrides.
An element–reaction–product table is used to find coefficients while balancing an equation representing a chemical reaction. Coefficients represent moles of a substance so that the number of atoms produced is equal to the number of atoms being reacted with. [1] This is the common setup: Element: all the elements that are in the reaction ...
For the primary formation reaction, a = 1.05 × 10 −6 and B = −0.47. Assuming an NH + 4 abundance of 3 × 10 − 7 {\displaystyle 3\times 10^{-7}} and an electron abundance of 10 −7 typical of molecular clouds, the formation will proceed at a rate of 1.6 × 10 −9 cm −3 s −1 in a molecular cloud of total density 10 5 cm −3 .