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In South Korea, the ri currently in use is a unit taken from the Han dynasty (206 BC–220 AD) li. It has a value of approximately 392.72 meters, or one tenth of the ri . The Aegukga , the national anthem of South Korea, mentions 3,000 ri , which roughly corresponds to 1,200 km , the approximate longitudinal span of the Korean peninsula .
Using the value 296 mm (11.7 in) for the Roman foot, an amphora quadrantal can be computed at approximately 25.9 L (5.7 imp gal; 6.8 US gal), so a sextarius (by the same method) would theoretically measure 540.3 ml (19.02 imp fl oz; 18.27 US fl oz), which is about 95% of an imperial pint (568 ml).
A U.K. deal equaled 7 ft × 6 ft × 2 + 1 ⁄ 2 in, while a U.S. deal equaled 12 ft × 11 in × 1 + 1 ⁄ 2 in. [7] Demiard – an old French unit of volume. When France metricated, it survived in Louisiana and Quebec. The demiard eventually became associated with the American and British half-pint rather than French units. [7] Firlot; Hekat ...
Taking this one stage further, the clue word can hint at the word or words to be abbreviated rather than giving the word itself. For example: "About" for C or CA (for "circa"), or RE. "Say" for EG, used to mean "for example". More obscure clue words of this variety include: "Model" for T, referring to the Model T.
Parsecs are used in astronomy to measure interstellar distances. A parsec is approximately 3.26 light-years or about 3.086×10 16 m (1.917×10 13 mi). Combining it with the "atto-" prefix (×10 −18) yields attoparsec (apc), a conveniently human-scaled unit of about 3.086 centimetres (1.215 in) that is used only humorously. [7]
A common unit in both measures throughout historic Greece was the cotyle or cotyla whose absolute value varied from one place to another between 210 ml and 330 ml. [1] The basic unit for both solid and liquid measures was the κύαθος (kyathos, plural: kyathoi).
The Hubble Space Telescope's Wide Field Camera 3 has the potential to provide a precision of 20 to 40 microarcseconds, enabling reliable distance measurements up to 5,000 parsecs (16,000 ly) for small numbers of stars. [5] [6] The Gaia space mission provided similarly accurate distances to most stars brighter than 15th magnitude. [7]
Add the clues together, plus 1 for each "space" in between. For example, if the clue is 6 2 3, this step produces the sum 6 + 1 + 2 + 1 + 3 = 13. Subtract this number from the total available in the row (usually the width or height of the puzzle). For example, if the clue in step 1 is in a row 15 cells wide, the difference is 15 - 13 = 2.