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  2. Cross-multiplication - Wikipedia

    en.wikipedia.org/wiki/Cross-multiplication

    where x is a variable we are interested in solving for, we can use cross-multiplication to determine that x = b c d . {\displaystyle x={\frac {bc}{d}}.} For example, suppose we want to know how far a car will travel in 7 hours, if we know that its speed is constant and that it already travelled 90 miles in the last 3 hours.

  3. Ancient Egyptian mathematics - Wikipedia

    en.wikipedia.org/wiki/Ancient_Egyptian_mathematics

    The fraction ⁠ 1 / 2 ⁠ was represented by a glyph that may have depicted a piece of linen folded in two. The fraction ⁠ 2 / 3 ⁠ was represented by the glyph for a mouth with 2 (different sized) strokes. The rest of the fractions were always represented by a mouth super-imposed over a number. [8]

  4. Order of operations - Wikipedia

    en.wikipedia.org/wiki/Order_of_operations

    For example, multiplication is granted a higher precedence than addition, and it has been this way since the introduction of modern algebraic notation. [2] [3] Thus, in the expression 1 + 2 × 3, the multiplication is performed before addition, and the expression has the value 1 + (2 × 3) = 7, and not (1 + 2) × 3 = 9.

  5. Fraction - Wikipedia

    en.wikipedia.org/wiki/Fraction

    A simple fraction (also known as a common fraction or vulgar fraction) [n 1] is a rational number written as a/b or ⁠ ⁠, where a and b are both integers. [9] As with other fractions, the denominator (b) cannot be zero. Examples include ⁠ 1 / 2 ⁠, − ⁠ 8 / 5 ⁠, ⁠ −8 / 5 ⁠, and ⁠ 8 / −5 ⁠.

  6. Singapore math - Wikipedia

    en.wikipedia.org/wiki/Singapore_math

    They would then solve the problem by inferring the shorter part to be 30. The bar model can be drawn as a comparison model to compare two bars of unequal lengths, which can then be used to solve a subtraction problem. The whole-part model can also be used to solve problems involving multiplication or division. [26]

  7. Extraneous and missing solutions - Wikipedia

    en.wikipedia.org/wiki/Extraneous_and_missing...

    To begin solving, we multiply each side of the equation by the least common denominator of all the fractions contained in the equation. In this case, the least common denominator is ( x − 2 ) ( x + 2 ) {\displaystyle (x-2)(x+2)} .