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Gas volume in the first zeppelin LZ 1: 1.1866 × 10 4: Amount of concrete in Trbovlje Chimney: 1.56 × 10 4: Quebec's 2001 output of maple syrup: 5.0 × 10 4: Typical volume of a large gasometer: 8.5–9.9 × 10 4: Volume of the Royal Albert Hall auditorium [4] 1.84 × 10 5: Volume of gas in the USS Macon zeppelin 2.118 90 × 10 5: Volume of ...
A cushion filled with stuffing. In geometry, the paper bag problem or teabag problem is to calculate the maximum possible inflated volume of an initially flat sealed rectangular bag which has the same shape as a cushion or pillow, made out of two pieces of material which can bend but not stretch.
Some SI units of volume to scale and approximate corresponding mass of water. To ease calculations, a unit of volume is equal to the volume occupied by a unit cube (with a side length of one). Because the volume occupies three dimensions, if the metre (m) is chosen as a unit of length, the corresponding unit of volume is the cubic metre (m 3).
One way to write the van der Waals equation is: [8] [9] [10] = where is pressure, is temperature, and = / is molar volume. In addition is the Avogadro constant, is the volume, and is the number of molecules (the ratio / is a physical quantity with base unit mole (symbol mol) in the SI).
Some SI units of volume to scale and approximate corresponding mass of water. A litre is a cubic decimetre, which is the volume of a cube 10 centimetres × 10 centimetres × 10 centimetres (1 L ≡ 1 dm 3 ≡ 1000 cm 3). Hence 1 L ≡ 0.001 m 3 ≡ 1000 cm 3; and 1 m 3 (i.e. a cubic metre, which is the SI unit for volume) is exactly 1000 L.
The partial volume of a particular gas is a fraction of the total volume occupied by the gas mixture, with unchanged pressure and temperature. In gas mixtures, e.g. air, the partial volume allows focusing on one particular gas component, e.g. oxygen.
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The ideal gas equation can be rearranged to give an expression for the molar volume of an ideal gas: = = Hence, for a given temperature and pressure, the molar volume is the same for all ideal gases and is based on the gas constant: R = 8.314 462 618 153 24 m 3 ⋅Pa⋅K −1 ⋅mol −1, or about 8.205 736 608 095 96 × 10 −5 m 3 ⋅atm⋅K ...