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cubic foot of natural gas: ≡ 1000 BTU IT = 1.055 055 852 62 × 10 6 J: cubic yard of atmosphere; standard cubic yard: cu yd atm; scy ≡ 1 atm × 1 yd 3 = 77.468 520 985 2288 × 10 3 J: electronvolt: eV ≡ e × 1 V ≡ 1.602 176 634 × 10 −19 J: erg : erg ≡ 1 g⋅cm 2 /s 2 = 10 −7 J foot-pound force: ft lbf ≡ g 0 × 1 lb × 1 ft = 1. ...
Both energy and torque can be expressed as a product of a force vector with a displacement vector (hence pounds and feet); energy is the scalar product of the two, and torque is the vector product. Although calling the torque unit "pound-foot" has been academically suggested, both are still commonly called "foot-pound" in colloquial usage.
Converts measurements to other units. Template parameters [Edit template data] This template prefers inline formatting of parameters. Parameter Description Type Status Value 1 The value to convert. Number required From unit 2 The unit for the provided value. Suggested values km2 m2 cm2 mm2 ha sqmi acre sqyd sqft sqin km m cm mm mi yd ft in kg g mg lb oz m/s km/h mph K C F m3 cm3 mm3 L mL cuft ...
{{convert|123|cuyd|m3+board feet}} → 123 cubic yards (94 m 3; 40,000 board feet) The following converts a pressure to four output units. The precision is 1 (1 decimal place), and units are abbreviated and linked.
pound/ounce-foot/ inch-hour-minute-second: foot-poundal: ftpdl ft⋅pdl 1.0 ft⋅pdl (0.042 J) foot-pound force: ftlbf ft⋅lbf 1.0 ft⋅lbf (1.4 J) ftlb-f ft⋅lb f: foot-pound: ftlb ft⋅lb inch-pound force: inlbf in⋅lbf 1.0 in⋅lbf (110 mJ) inlb-f in⋅lb f: inch-pound: inlb in⋅lb inch-ounce force: inozf in⋅ozf 1.0 in⋅ozf (7.1 mJ ...
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ft (foot) ft long code "foot" outputs foot (and never feet) Use of ′ and ″ symbols violates MOSNUM so is not provided. 1.0 ft (0.30 m) ftin (feet and inches) ft m (foot m) inch: in in Use of ′ and ″ symbols violates MOSNUM so is not provided. 1.0 in (25 mm) in cm; in mm; Other: nautical mile: nmi nmi the international standard nautical mile
Units for other physical quantities are derived from this set as needed. In English Engineering Units, the pound-mass and the pound-force are distinct base units, and Newton's Second Law of Motion takes the form = where is the acceleration in ft/s 2 and g c = 32.174 lb·ft/(lbf·s 2).