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US spelling: cubic meter one kilolitre 1.0 m 3 (35 cu ft) cubic centimetre: cm3 cm 3: US spelling: cubic centimeter one millilitre 1.0 cm 3 (0.061 cu in) cc cc cubic millimetre: mm3 mm 3: US spelling: cubic millimeter: 1.0 mm 3 (6.1 × 10 −5 cu in) non-SI metric: kilolitre: kl kl US spelling: kiloliter one cubic metre 1.0 kl (35 cu ft) kL kL ...
The apple, therefore, contains 158 mg potassium (0.72/100 X 22 g). Dried apple contains the same concentration of potassium on a dry matter basis (0.72%), but is only 32% water (68% dry matter). So 138 g of dried apple contains 93.8 g dry matter and 675 mg potassium (0.72/100 x 93.8 g).
For the dry bulk density, the sample is oven dried and weighed, giving the mass of soil solids, M s. The relationship between these two masses is M t = M s + M l, where M l is the mass of substances lost on oven drying (often, mostly water). The dry and wet bulk densities are calculated as Dry bulk density = mass of soil/ volume as a whole
Dry measures are units of volume to measure bulk commodities that are not fluids and that were typically shipped and sold in standardized containers such as barrels.They have largely been replaced by the units used for measuring volumes in the metric system and liquid volumes in the imperial system but are still used for some commodities in the US customary system.
The specific weight, also known as the unit weight (symbol γ, the Greek letter gamma), is a volume-specific quantity defined as the weight W divided by the volume V of a material: = / Equivalently, it may also be formulated as the product of density, ρ, and gravity acceleration, g: = Its unit of measurement in the International System of Units (SI) is newton per cubic metre (N/m 3), with ...
The dry gallon's implicit value in the US system was originally one eighth of the Winchester bushel, which was a cylindrical measure of 18.5 inches (469.9 mm) in diameter and 8 inches (203.2 mm) in depth, making it an irrational number of cubic inches; its value to seven significant digits was 268.8025 cubic inches (4.404884 litres), from an ...
An aqueous solution containing 2 g of glucose and 2 g of fructose per 100 g of solution contains 2/100=2% glucose on a wet basis, but 2/4=50% glucose on a dry basis.If the solution had contained 2 g of glucose and 3 g of fructose, it would still have contained 2% glucose on a wet basis, but only 2/5=40% glucose on a dry basis.
Example 1: If a block of solid stone weighs 3 kilograms on dry land and 2 kilogram when immersed in a tub of water, then it has displaced 1 kilogram of water. Since 1 liter of water weighs 1 kilogram (at 4 °C), it follows that the volume of the block is 1 liter and the density (mass/volume) of the stone is 3 kilograms/liter.