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The most direct method is to truncate the Maclaurin series for each of the trigonometric functions. Depending on the order of the approximation , cos θ {\displaystyle \textstyle \cos \theta } is approximated as either 1 {\displaystyle 1} or as 1 − 1 2 θ 2 {\textstyle 1-{\frac {1}{2}}\theta ^{2}} .
The Taylor series of any polynomial is the polynomial itself.. The Maclaurin series of 1 / 1 − x is the geometric series + + + +. So, by substituting x for 1 − x, the Taylor series of 1 / x at a = 1 is
The case α = 1 gives the series 1 + x + x 2 + x 3 + ..., where the coefficient of each term of the series is simply 1. The case α = 2 gives the series 1 + 2x + 3x 2 + 4x 3 + ..., which has the counting numbers as coefficients. The case α = 3 gives the series 1 + 3x + 6x 2 + 10x 3 + ..., which has the triangle numbers as coefficients.
A Laurent series is a generalization of the Taylor series, allowing terms with negative exponents; it takes the form = and converges in an annulus. [6] In particular, a Laurent series can be used to examine the behavior of a complex function near a singularity by considering the series expansion on an annulus centered at the singularity.
The geometric series 1 / 3 = 1 / 4 + 1 / 16 + 1 / 64 + 1 / 256 + ⋯ or 1 / 3 = 1 / 2 − 1 / 4 + 1 / 8 − 1 / 16 + ⋯ can be used as a basis for the bisections. An approximation to any degree of accuracy can be obtained in a finite number of steps.
where p = 0.3275911, a 1 = 0.254829592, a 2 = −0.284496736, a 3 = 1.421413741, a 4 = −1.453152027, a 5 = 1.061405429 All of these approximations are valid for x ≥ 0 . To use these approximations for negative x , use the fact that erf x is an odd function, so erf x = −erf(− x ) .
In algebraic geometry, the trisectrix of Maclaurin is a cubic plane curve notable for its trisectrix property, meaning it can be used to trisect an angle. It can be defined as locus of the point of intersection of two lines , each rotating at a uniform rate about separate points, so that the ratio of the rates of rotation is 1:3 and the lines ...
Each side of the green triangle is exactly 1 / 3 the size of a side of the large blue triangle and therefore has exactly 1 / 9 the area. Similarly, each yellow triangle has 1 / 9 the area of a green triangle, and so forth. All of these triangles can be represented in terms of geometric series: the blue triangle's area is ...