Search results
Results From The WOW.Com Content Network
Surface area to volume ratio of a sphere equals to 3/r, where r is the sphere's radius. Surface area of a sphere with radius r equals to 4pir^2. The volume of this sphere is 4/3pir^3. Ratio of the surface area to volume, therefore, equals to (4pir^2)/ (4/3pir^3)=4 (3/4) (pi/pi) (r^2/r^3)=3/r.
A = int dA An area element on a sphere has constant radius r, and two angles. One is longitude phi, which varies from 0 to 2pi. The other one is the angle with the vertical. To avoid counting twice, that angle only varies between 0 and pi. So the area element is dA = r d theta r sin theta d phi = r^2 sin theta d theta d phi Integrated over the whole sphere gives A = int_0^pi sin theta d theta ...
The surface area of Mercury is 19477"miles"^2 SA = 4 pi r^2 r = 1550 SA = 4 pi 1550^2 SA = 12.566 xx 1550^2 SA = 19477.88"mi"^2
Explanation: to get r, square root r2. divide the surface area by 4pi and square root it. let r be the radius the surface area of a sphere is 4 x pi x r^2 thus, to find the radius, firstly, divide the surface area by 4 and pi, and you'll get r^2 to get r, square root r^2.
The Jacobian for Spherical Coordinates is given by J = ρ2sinϕ. And so we can calculate the surface area of a sphere of radius r using a double integral: A = ∫∫R dS. where R = {(x,y,z) ∈ R3 ∣ x2 +y2 + z2 = r2} ∴ A = ∫ π 0 ∫ 2π 0 r2sinϕ dθ dϕ. If we look at the inner integral we have: So our integral becomes: It is easier to ...
The surface area of a sphere of radius #r# is #4 pi r^2#. Imagine dividing a sphere into a large number of slender pyramids with base at the surface and top at the centre of the sphere. The base of each pyramid will not be quite flat, but the more pyramids you divide the sphere into, the flatter the base of each will be.
With the formula we can calculate the Surface Area. S = 4πr2. We know the radius (r) to be 8f t. S = 4 × π× 82. S = 4 × π× 64. S = 256π. The surface area of the sphere is 256pi square feet. With the formula we can calculate the Surface Area. S=4pir^2 We know the radius (r) to be 8ft.
The area of the cross section is 380.134 square inches The cross section, of a sphere formed by a plane intersecting the sphere at an equator, is a circle of the same radius as that of the sphere itself (as may be seen from picture below). Hence, the area of the cross section is pir^2=pixx11^2=121pi = 121xx3.1416 ~=380.134 square inches.
A = 4πr2. So the surface area to volume ratio is. SA V = 4π r2 3 4π r3 = 1 3r. The surface area to volume ratio is "1/3r":1, where r is the radius of the sphere. The formula for the volume of a sphere is V = 4/3πr^3, where r is the radius of the sphere. The formula for the area of a sphere is.
Explanation: R - The average radius of the Earth. Assume that the Earth is a perfect sphere. A=4piR^2 A - Area of the Earth R - The average radius of the Earth. Assume that the Earth is a perfect sphere.