When.com Web Search

Search results

  1. Results From The WOW.Com Content Network
  2. Vieta's formulas - Wikipedia

    en.wikipedia.org/wiki/Vieta's_formulas

    A method similar to Vieta's formula can be found in the work of the 12th century Arabic mathematician Sharaf al-Din al-Tusi. It is plausible that the algebraic advancements made by Arabic mathematicians such as al-Khayyam, al-Tusi, and al-Kashi influenced 16th-century algebraists, with Vieta being the most prominent among them. [2] [3]

  3. Vieta jumping - Wikipedia

    en.wikipedia.org/wiki/Vieta_jumping

    For any (a, b) satisfying the given condition, let k = ⁠ a 2 + b 2 + 1 / ab ⁠ and rearrange and substitute to get x 2 − (kb) x + (b 2 + 1) = 0. One root to this quadratic is a, so by Vieta's formulas the other root may be written as follows: x 2 = kb − a = ⁠ b 2 + 1 / a ⁠. The first equation shows that x 2 is an integer and the ...

  4. Viète's formula - Wikipedia

    en.wikipedia.org/wiki/Viète's_formula

    Viète's formula, as printed in Viète's Variorum de rebus mathematicis responsorum, liber VIII (1593). In mathematics, Viète's formula is the following infinite product of nested radicals representing twice the reciprocal of the mathematical constant π: = + + + It can also be represented as = = ⁡ +.

  5. Cubic equation - Wikipedia

    en.wikipedia.org/wiki/Cubic_equation

    Vieta's substitution is a method introduced by François Viète (Vieta is his Latin name) in a text published posthumously in 1615, which provides directly the second formula of § Cardano's method, and avoids the problem of computing two different cube roots.

  6. Talk:Vieta's formulas - Wikipedia

    en.wikipedia.org/wiki/Talk:Vieta's_formulas

    I think the last sentence summarizes it well. In English at least, the tradition has been to use Vieta, and Viete is an overcorrection (outside historical or biographic contexts), like saying "Hero's formula" with Greek pronunciation, instead than Heron's formula. 73.89.25.252 04:52, 13 June 2020 (UTC)

  7. Lifting-the-exponent lemma - Wikipedia

    en.wikipedia.org/wiki/Lifting-the-exponent_lemma

    Since , the factors of 5 are addressed by noticing that since the residues of modulo 5 follow the cycle ,,, and those of follow the cycle ,,,, the residues of modulo 5 cycle through the sequence ,,,. Thus, 5 ∣ 149 n − 2 n {\displaystyle 5\mid 149^{n}-2^{n}} iff n = 4 k {\displaystyle n=4k} for some positive integer k {\displaystyle k} .

  8. Talk:Viète's formula - Wikipedia

    en.wikipedia.org/wiki/Talk:Viète's_formula

    1 The above formula is a result of one of Leonhard Euler's formula. 1 comment. 2 reference. 1 comment. 3 request for mention of "Osler product" 2 comments. 4 Did you ...

  9. Reduced residue system - Wikipedia

    en.wikipedia.org/wiki/Reduced_residue_system

    The so-called totatives 1, 5, 7 and 11 are the only integers in this set which are relatively prime to 12, and so the corresponding reduced residue system modulo 12 is {1, 5, 7, 11}. The cardinality of this set can be calculated with the totient function: φ(12) = 4. Some other reduced residue systems modulo 12 are: {13,17,19,23} {−11,−7 ...