Search results
Results From The WOW.Com Content Network
The ideal gas equation can be rearranged to give an expression for the molar volume of an ideal gas: = = Hence, for a given temperature and pressure, the molar volume is the same for all ideal gases and is based on the gas constant: R = 8.314 462 618 153 24 m 3 ⋅Pa⋅K −1 ⋅mol −1, or about 8.205 736 608 095 96 × 10 −5 m 3 ⋅atm⋅K ...
The number of wraps will act as a gauge to assess the thickness of unmarked yarn; for example 12 wraps per inch is 12 WPI, and is used to calculate how much yarn is required for various articles, [3] so that 12 is equivalent to 8 ply (worsted weight, medium weight) yarn.
Given the linear density and weight the yarn length can be calculated; for example: l/m = 1693 × l m /Nec × m/kg, where l/m is the yarn length in metres, l m /Nec is the English cotton count and m/kg is the yarn weight in kilograms. The following length units are defined. Bundle: usually 10 lb (4.5 kg)
The Craft Yarn Council of America promotes a standardized industry system for measuring yarn weight, where weights are numbered from 0 (finest) to 7 (thickest). [31] Each weight can be described by a number and name: Size 0 yarn is called Lace, size 1 is Super Fine, size 2 is Fine, size 3 is Light, size 4 is Medium, size 5 is Bulky, size 6 is ...
It is the same concept as volume percent (vol%) except that the latter is expressed with a denominator of 100, e.g., 18%. The volume fraction coincides with the volume concentration in ideal solutions where the volumes of the constituents are additive (the volume of the solution is equal to the sum of the volumes of its ingredients).
Using the number density as a function of spatial coordinates, the total number of objects N in the entire volume V can be calculated as = (,,), where dV = dx dy dz is a volume element. If each object possesses the same mass m 0 , the total mass m of all the objects in the volume V can be expressed as m = ∭ V m 0 n ( x , y , z ) d V ...
For a substance X with a specific volume of 0.657 cm 3 /g and a substance Y with a specific volume 0.374 cm 3 /g, the density of each substance can be found by taking the inverse of the specific volume; therefore, substance X has a density of 1.522 g/cm 3 and substance Y has a density of 2.673 g/cm 3. With this information, the specific ...
Any extensive quantity E for a sample can be divided by the sample's volume, to become the "E density" for the sample; similarly, any extensive quantity "E" can be divided by the sample's mass, to become the sample's "specific E"; extensive quantities "E" which have been divided by the number of moles in their sample are referred to as "molar E".