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Depends on what you want to do: to read the value as an ascii code, you can write. char a = 'a'; int ia = (int)a; /* note that the int cast is not necessary -- int ia = a would suffice */. to convert the character '0' -> 0, '1' -> 1, etc, you can write. char a = '4'; int ia = a - '0'; /* check here if ia is bounded by 0 and 9 */.
1. Converting our integer value to std::string so we can know how long (how long number of digits). Then we creating char array length of string letter size +1, so we can copy our value to string then char array. std::string strData = std::to_string(data); char* temp = new char[strData.length() + 1];
Convert char to int in C and C++ (14 answers) Closed 3 years ago . I have a string of digits, e.g. "123456789", and I need to extract each one of them to use them in a calculation.
I need to convert a char* to an integer. For example: data.SetBytFldPos(*attribute->value()); The value in the attribute class is a char*. 'SetBytFldPos" takes an int.
Yes -- in C and C++, char is just a small integer type (typically with a range from -128 to +127). When you do math on it, it'll normally be converted to int automatically, so you don't even need your cast. As an aside, you really don't want to use strlen(s) inside the stopping condition for your for-loop.
3. Usually you should declare characters as char and use int for integers being capable of holding bigger values. On most systems a char occupies a byte which is 8 bits. Depending on your system this char might be signed or unsigned by default, as such it will be able to hold values between 0-255 or -128-127.
In order to convert them to int you need to subtract the ASCII value of '0' from it. And also if you are operating in a for loop you don't need to increment i explicitly. That is maybe the reason you skip characters. This may help: cout << total_line[i] <<endl; int d = total_line[i]; cout << d - '0' << endl;
I would like to convert a char to its ASCII int value. I could fill an array with all possible values and compare to that, but it doesn't seems right to me. I would like something like. char mychar = "k" public int ASCItranslate(char c) return c ASCItranslate(k) // >> Should return 107 as that is the ASCII value of 'k'.
22. +25. If you really want to convert a pointer to a constant character into an unsigned int then you should use in c++: const char* p; unsigned int i = reinterpret_cast<unsigned int>( p ); This converts the address to which the pointer points to into an unsigned integer.
1. What you are doing is treating with the ASCII code of the chars, each char has an ASCII value assigned. Now, playing a little with the ASCII of each char you can do things like: int a; a = 'a' - 'A' ; printf("%d", a); And get 32 as output, due to the ASCII value to 'a' = 97 and for 'A' = 65, then you have 97-65 = 32.