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Isoelectronicity is a phenomenon observed when two or more molecules have the same structure (positions and connectivities among atoms) and the same electronic configurations, but differ by what specific elements are at certain locations in the structure. For example, CO, NO +, and N 2 are isoelectronic, while CH 3 COCH 3 and CH 3 N = NCH 3 are ...
Isostructural chemical compounds have similar chemical structures."Isomorphous" when used in the relation to crystal structures is not synonymous: in addition to the same atomic connectivity that characterises isostructural compounds, isomorphous substances crystallise in the same space group and have the same unit cell dimensions. [1]
The bond order itself is the number of electron pairs (covalent bonds) between two atoms. [3] For example, in diatomic nitrogen N≡N, the bond order between the two nitrogen atoms is 3 (triple bond). In acetylene H–C≡C–H, the bond order between the two carbon atoms is also 3, and the C–H bond order is 1 (single bond).
Borazine, also known as borazole, inorganic benzene, is an inorganic compound with the chemical formula B 3 H 6 N 3. In this cyclic compound, the three BH units and three NH units alternate. The compound is isoelectronic and isostructural with benzene. For this reason borazine is sometimes referred to as “inorganic benzene”.
This type of bond is sometimes called a "banana bond". B 2 H 6 is isoelectronic with C 2 H 6 2+, which would arise from the diprotonation of the planar molecule ethylene. [8] Diborane is one of many compounds with such unusual bonding. [9] Of the other elements in group IIIA, gallium is known to form a similar compound digallane, Ga 2 H 6.
The compounds Co(NO)(CO) 3 and Ni(CO) 4 illustrate the analogy between NO + and CO. In an electron-counting sense, two linear NO ligands are equivalent to three CO groups. This trend is illustrated by the isoelectronic pair Fe(CO) 2 (NO) 2 and [Ni(CO) 4]. [3] These complexes are isoelectronic and, incidentally, both obey the 18-electron rule.
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Natural bond orbital (NBO) analysis of C 4 H 4 BH has been performed in order to understand the bonding of borole in the familiar Lewis picture. [5] According to the computational results, the occupancy of the two C−C π orbitals is about 1.9, with a tiny amount of electronic charge (an occupancy of 0.13) delocalised on the out-of-plane boron p orbital, illustrated below.