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Since the velocity of the object is the derivative of the position graph, the area under the line in the velocity vs. time graph is the displacement of the object. (Velocity is on the y-axis and time on the x-axis. Multiplying the velocity by the time, the time cancels out, and only displacement remains.)
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Trajectory of a particle with initial position vector r 0 and velocity v 0, subject to constant acceleration a, all three quantities in any direction, and the position r(t) and velocity v(t) after time t. The initial position, initial velocity, and acceleration vectors need not be collinear, and the equations of motion take an almost identical ...
Date/Time Thumbnail Dimensions User Comment; current: 01:22, 25 February 2007: 496 × 504 (111 KB) Stannered {{Information |Description=Example of a en:velocity vs. time graph, and the relationship between velocity v, en:displacement s, and en:acceleration a. Traced in en:Inkscape from an original drawn in en:Microsoft Paint. |Source=[[:
In terms of a displacement-time (x vs. t) graph, the instantaneous velocity (or, simply, velocity) can be thought of as the slope of the tangent line to the curve at any point, and the average velocity as the slope of the secant line between two points with t coordinates equal to the boundaries of the time period for the average velocity.
Download as PDF; Printable version ... is useful in many areas of computer ... teach mathematics to students for significant amounts of time. [189] During school ...
Propagation of a wave packet demonstrating a phase velocity greater than the group velocity. This shows a wave with the group velocity and phase velocity going in different directions. The group velocity is positive, while the phase velocity is negative. [1] The phase velocity of a wave is the rate at which the wave propagates in any medium.