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Example of addition with carry. The black numbers are the addends, the green number is the carry, and the blue number is the sum. In the rightmost digit, the addition of 9 and 7 is 16, carrying 1 into the next pair of the digit to the left, making its addition 1 + 5 + 2 = 8. Therefore, 59 + 27 = 86.
5 + 5 → 0, carry 1 (since 5 + 5 = 10 = 0 + (1 × 10 1)) 7 + 9 → 6, carry 1 (since 7 + 9 = 16 = 6 + (1 × 10 1)) This is known as carrying. [41] When the result of an addition exceeds the value of a digit, the procedure is to "carry" the excess amount divided by the radix (that is, 10/10) to the left, adding it to the next positional value.
A typical example of carry is in the following pencil-and-paper addition: 1 27 + 59 ---- 86 7 + 9 = 16, and the digit 1 is the carry. The opposite is a borrow, as in −1 47 − 19 ---- 28 Here, 7 − 9 = −2, so try (10 − 9) + 7 = 8, and the 10 is got by taking ("borrowing") 1 from the next digit to the left. There are two ways in which ...
The leading digit "1" of the result is then discarded. The method of complements is especially useful in binary (radix 2) since the ones' complement is very easily obtained by inverting each bit (changing "0" to "1" and vice versa). And adding 1 to get the two's complement can be done by simulating a carry into the least significant bit. For ...
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A: value is either 1 or 11. 3: value is 3 and the next player loses a turn. 4: value is 0 and the order of play is reversed. Once the game is down to two players, whoever played a 4 takes another turn instead. 9: value is 99 regardless of the previous total value. 10: value is either -10 or +10. J: value is 10. Q: value is 10. K: value is 0.