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30,561 10 3,G81 20 ÷ ÷ ÷ 61 10 31 20 = = = 501 10 151 20 30,561 10 ÷ 61 10 = 501 10 3,G81 20 ÷ 31 20 = 151 20 ÷ = (black) The divisor goes into the first two digits of the dividend one time, for a one in the quotient. (red) fits into the next two digits once (if rotated), so the next digit in the quotient is a rotated one (that is, a five). (blue) The last two digits are matched once for ...
Related algorithms have existed since the 12th century. [2] Al-Samawal al-Maghribi (1125–1174) performed calculations with decimal numbers that essentially require long division, leading to infinite decimal results, but without formalizing the algorithm. [3]
Take each digit of the number (371) in reverse order (173), multiplying them successively by the digits 1, 3, 2, 6, 4, 5, repeating with this sequence of multipliers as long as necessary (1, 3, 2, 6, 4, 5, 1, 3, 2, 6, 4, 5, ...), and adding the products (1×1 + 7×3 + 3×2 = 1 + 21 + 6 = 28). The original number is divisible by 7 if and only if ...
For division to always yield one number rather than an integer quotient plus a remainder, the natural numbers must be extended to rational numbers or real numbers. In these enlarged number systems , division is the inverse operation to multiplication, that is a = c / b means a × b = c , as long as b is not zero.
In base 10, ten different digits 0, ..., 9 are used and the position of a digit is used to signify the power of ten that the digit is to be multiplied with, as in 304 = 3×100 + 0×10 + 4×1 or more precisely 3×10 2 + 0×10 1 + 4×10 0. Zero, which is not needed in the other systems, is of crucial importance here, in order to be able to "skip ...
Cancelling 0 from both sides yields =, a false statement. The fallacy here arises from the assumption that it is legitimate to cancel 0 like any other number, whereas, in fact, doing so is a form of division by 0. Using algebra, it is possible to disguise a division by zero [17] to obtain an invalid proof. For example: [18]