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One slug is a mass equal to 32.17405 lb (14.59390 kg) based on standard gravity, the international foot, and the avoirdupois pound. [3] In other words, at the Earth's surface (in standard gravity), an object with a mass of 1 slug weighs approximately 32.17405 lbf or 143.1173 N. [4] [5]
≡ 1 ⁄ 700 lb av = 647.9891 mg slug; geepound: slug ≡ g 0 × 1 lb av × 1 s 2 /ft ≈ 14.593 903 kg: stone: st ≡ 14 lb av = 6.350 293 18 kg: ton, assay (long) AT ≡ 1 mg × 1 long ton ÷ 1 oz t = 32. 6 g ton, assay (short) AT ≡ 1 mg × 1 short ton ÷ 1 oz t = 29.1 6 g ton, long: long tn or ton ≡ 2240 lb = 1 016.046 9088 kg: ton ...
A slug has a mass of 32.174049 lb. A pound-force is the amount of force required to accelerate a slug at a rate of 1 ft/s 2, so: ... 1 lb F: ≈ 4.448 222 N: ≈ ...
5 / 9 k Units for other physical quantities are derived from this set as needed. In English Engineering Units, the pound-mass and the pound-force are distinct base units, and Newton's Second Law of Motion takes the form F = m a g c {\displaystyle F=m{\frac {a}{g_{\mathrm {c} }}}} where a {\displaystyle a} is the acceleration in ft/s 2 ...
The conversion for the poundal is given by 1 pdl = 1 lb·ft/s 2 = 0.138 254 954 376 N (precisely). [1] To convert between the absolute and gravitational FPS systems one needs to fix the standard acceleration g which relates the pound to the pound-force. [citation needed] =
Standard sea-level conditions (SSL), [1] also known as sea-level standard (SLS), defines a set of atmospheric conditions for physical calculations.The term "standard sea level" is used to indicate that values of properties are to be taken to be the same as those standard at sea level, and is done to define values for use in general calculations.
Since a pound of force (pound force) accelerates a pound of mass at 32.174 049 ft/s 2 (9.80665 m/s 2; the acceleration of gravity, g), we can scale down the unit of force to compensate, giving us one that accelerates 1 pound mass at 1 ft/s 2 rather than at 32.174 049 ft/s 2; and that is the poundal, which is approximately 1 ⁄ 32 pound force.
For example, the freezing point of water is 0 °C and 32 °F, and a 5 °C change is the same as a 9 °F change. Thus, to convert from units of Fahrenheit to units of Celsius, one subtracts 32 °F (the offset from the point of reference), divides by 9 °F and multiplies by 5 °C (scales by the ratio of units), and adds 0 °C (the offset from the ...