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For example, 1 / 4 , 5 / 6 , and −101 / 100 are all irreducible fractions. On the other hand, 2 / 4 is reducible since it is equal in value to 1 / 2 , and the numerator of 1 / 2 is less than the numerator of 2 / 4 . A fraction that is reducible can be reduced by dividing both the numerator ...
Nguyễn Thanh Hiền; Personal information; Full name: Nguyễn Thanh Hiền: Date of birth 16 April 1993 (age 31) Place of birth: Tam Nông, Đồng Tháp, Vietnam: Height: 1.75 m (5 ft 9 in) Position(s) Right Back, Right Winger: Youth career; 2008–2010: Đồng Tháp: Senior career* Years: Team: Apps (Gls) 2011–2016: Đồng Tháp: 51 (4 ...
Nguyễn Thần Hiến (1856–1914) was a Vietnamese scholar-gentry anti-colonial revolutionary activist who advocated independence from French colonial rule. He was a contemporary of Phan Bội Châu and Phan Chu Trinh and was regarded as the most prominent southerner of his generation of scholar-gentry activists.
Nguyễn Thanh Hiền or simply Hien (born 6 March 1994) is a Hungarian pop singer of Vietnamese descent who competed in the Hungarian Megasztár sixth season and was the fifth runner up. Biography [ edit ]
Also the converse is true: The decimal expansion of a rational number is either finite, or endlessly repeating. Finite decimal representations can also be seen as a special case of infinite repeating decimal representations. For example, 36 ⁄ 25 = 1.44 = 1.4400000...; the endlessly repeated sequence is the one-digit sequence "0".
5.1 Canonical form and repetend. ... can be used to obtain the continued fraction expansion in canonical form ... whose decimal value is approx. 10.67707 ...
Most decimal fractions (or most fractions in general) cannot be represented exactly as a fraction with a denominator that is a power of two. For example, the simple decimal fraction 0.3 (3 ⁄ 10) might be represented as 5404319552844595 ⁄ 18014398509481984 (0.299999999999999988897769…). This inexactness causes many problems that are ...
where c 1 = 1 / a 1 , c 2 = a 1 / a 2 , c 3 = a 2 / a 1 a 3 , and in general c n+1 = 1 / a n+1 c n . Second, if none of the partial denominators b i are zero we can use a similar procedure to choose another sequence { d i } to make each partial denominator a 1: