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The reason for direct AC-AC conversion is the size and mass of the DC choke coil (or capacitor array). You don't want to have that e.g. in a rubber-wheeled subway car or aircraft. In iron-wheeled trains it depends, because more mass means better friction. That doesn't apply to buildings. You cannot save on valves (transistors or thyristors).
2 Answers. Sorted by: 5. Summary: Watts out DC = 75% to 90% of AC Watts in, in most cases. See below: At 100% efficiency ADC Watts out = AC Watts in. Energy is 'conserved" and energy = Watts x time. eg we often measure energy in Watt.seconds = Watts x seconds operated = Joules. The efficiency of conversion depends on the technology.
In the screenshot that you posted your inverter is consuming 416 watts (26 volts * 16 amps) from your panels. Some of this is going toward the AC load on the inverter (289 watts), some is being used to charge the battery that is at 80% of capacity, and the remainder is inverter/charger inefficiencies. Nothing seems out of order.
Mainly used for powering lamps. Not solid core, 2*0.75mm² cable) laying around, that's rated for 1380 watts. Our wall sockets provide 230V at 50 hertz, so 1380 watts is 6 amps. I've got a 3d printer, on which I want to change the power supply. The current one is 21 amps at 12V DC, or 252 watts.
Also, oscillators for generating frequencies (used as clock for a CPU ar anything else) are generatring AC (often with a DC-Offset) from DC. BLDC motor drivers are also generating AC from DC (mostly in the range of safety low voltage). So AC to DC conversion is all around you all the time. In the simplest case it's just switching on and off the ...
The goal is to convert the output of an astable multivibrator into a sine wave that can drive a transformer in a decent way. The way to do this:connect two low pass filters one to another.One will have a square wave at the input and convert it into a triangle wave.The other will receive it and convert into a sine wave.
50 A = P(W) / 12 VDC. 50 A * 12 VDC = 600 W. And since the information about continuous DC power is given as 320 W, is the calculation for DC to AC power conversion efficiency below correct? 320 W / 600 W = 0.53 efficiency. If the calculations above are wrong, could you please explain and correct me?
2. I want to replace my wall switch with a smart switch which can be controlled by an ESP32. I need to use AC to DC conversion to get 3.3 V from 240 V, 50 Hz. Some of the wall outlets have only phase and neutral, always directly connected to the appliance. In that case, I can't install an AC to DC converter for smart switch replacement.
However at the other end of the scale, very long transmission lines and undersea cables have less loss using DC, even after DC/AC conversion at each end. So in deciding which is more efficient you have to consider not just the component that changes the voltage, but what associated losses may occur in other parts of the system.
There will be almost no difference in the conversion efficiency of an AC-DC versus a DC-DC convertor. For example if you used a PC power supply to convert 120/240 to 12VDC (I'll simply ignore the other voltages produced), most modern SMPS supplies are at least 85% efficient: