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Triglycerides of vegetable and animal origin are reacted with methanol in the presence of alkali metal methanolates to form the corresponding fatty methyl esters. [ 9 ] [ 3 ] Potassium methoxide allows a facilitated formation of fatty soaps in comparison to the (lower-priced) sodium methoxide (here potassium salts of the fatty acids from the ...
The tables below provides information on the variation of solubility of different substances (mostly inorganic compounds) in water with temperature, at one atmosphere pressure. Units of solubility are given in grams of substance per 100 millilitres of water (g/100 ml), unless shown otherwise. The substances are listed in alphabetical order.
Thus on a molar basis, KOH is slightly more soluble than NaOH. Lower molecular-weight alcohols such as methanol, ethanol, and propanols are also excellent solvents. They participate in an acid-base equilibrium. In the case of methanol the potassium methoxide (methylate) forms: [15] KOH + CH 3 OH → CH 3 OK + H 2 O
The following chart shows the solubility of various ionic compounds in water at 1 atm pressure and room temperature (approx. 25 °C, 298.15 K). "Soluble" means the ionic compound doesn't precipitate, while "slightly soluble" and "insoluble" mean that a solid will precipitate; "slightly soluble" compounds like calcium sulfate may require heat to precipitate.
Methanol is primarily converted to formaldehyde, which is widely used in many areas, especially polymers. The conversion entails oxidation: 2 CH 3 OH + O 2 → 2 CH 2 O + 2 H 2 O. Acetic acid can be produced from methanol. The Cativa process converts methanol into acetic acid. [35] Methanol and isobutene are combined to give methyl tert-butyl ...
It can be prepared by treating a potassium-containing base such as potassium hydroxide or potassium carbonate with acetic acid: CH 3 COOH + KOH → CH 3 COOK + H 2 O. This sort of reaction is known as an acid-base neutralization reaction. At saturation, the sesquihydrate in water solution (CH 3 COOK·1½H 2 O) begins to form semihydrate at 41.3 ...
Here is a similar formula from the 67th edition of the CRC handbook. Note that the form of this formula as given is a fit to the Clausius–Clapeyron equation, which is a good theoretical starting point for calculating saturation vapor pressures: log 10 (P) = −(0.05223)a/T + b, where P is in mmHg, T is in kelvins, a = 38324, and b = 8.8017.
This Wikipedia page provides a comprehensive list of boiling and freezing points for various solvents.