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The hydraulic diameter is the equivalent circular configuration with the same circumference as the wetted perimeter. The area of a circle of radius R is . Given the area of a non-circular object A, one can calculate its area-equivalent radius by setting = or, alternatively:
Earth radius (denoted as R 🜨 or R E) is the distance from the center of Earth to a point on or near its surface. Approximating the figure of Earth by an Earth spheroid (an oblate ellipsoid), the radius ranges from a maximum (equatorial radius, denoted a) of nearly 6,378 km (3,963 mi) to a minimum (polar radius, denoted b) of nearly 6,357 km (3,950 mi).
Mathematically, the radius of a circle is half the diameter, so the correct turning radius in this example would be 11.6 m / 2 = 5.8 m. However, another source lists the turning radius of the same vehicle as also being 11.6 m, [ 5 ] which is the turning diameter.
Equivalent diameter – Radius of a circle or sphere equivalent to a non-circular or non-spherical object Eratosthenes , who calculated the diameter of the Earth around 240 BC. Graph or network diameter – Length of shortest path between two nodes of a graph
Let A′ be the point opposite A on the circle, so that A′A is a diameter, and A′AB is an inscribed triangle on a diameter. By Thales' theorem, this is a right triangle with right angle at B. Let the length of A′B be c n, which we call the complement of s n; thus c n 2 +s n 2 = (2r) 2. Let C bisect the arc from A to B, and let C′ be the ...
All radii, once calculated, are divided by 6.957 × 10 8 to convert from m to R ☉.. AD radius determined from angular diameter and distance =, (/) =, = D is multiplied by 3.0857 × 10 19 to convert from kpc to m
The hydraulic diameter, D H, is a commonly used term when handling flow in non-circular tubes and channels. Using this term, one can calculate many things in the same way as for a round tube. When the cross-section is uniform along the tube or channel length, it is defined as [1] [2] =, where
Since the diameter is twice the radius, the "missing" part of the diameter is (2r − x) in length. Using the fact that one part of one chord times the other part is equal to the same product taken along a chord intersecting the first chord, we find that (2r − x)x = (y / 2) 2. Solving for r, we find the required result.