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where f k is the k-th Fibonacci number. The first condition is the Fermat primality test using base 2. In general, if p ≡ a (mod x 2 +4), where a is a quadratic non-residue (mod x 2 +4) then p should be prime if the following conditions hold: 2 p−1 ≡ 1 (mod p), f(1) p+1 ≡ 0 (mod p), f(x) k is the k-th Fibonacci polynomial at x.
For example, take n = 71. Then n − 1 = 70 and the prime factors of 70 are 2, 5 and 7.We randomly select an a=17 < n.Now we compute: (). For all integers a it is known that
Using fast algorithms for modular exponentiation and multiprecision multiplication, the running time of this algorithm is O(k log 2 n log log n) = Õ(k log 2 n), where k is the number of times we test a random a, and n is the value we want to test for primality; see Miller–Rabin primality test for details.
The AKS primality test (also known as Agrawal–Kayal–Saxena primality test and cyclotomic AKS test) is a deterministic primality-proving algorithm created and published by Manindra Agrawal, Neeraj Kayal, and Nitin Saxena, computer scientists at the Indian Institute of Technology Kanpur, on August 6, 2002, in an article titled "PRIMES is in P". [1]
However, the terms of the sequence will be different and a non-zero Lucas-Lehmer residue for non-prime M p will have a different numerical value from the non-zero value calculated when s 0 = 4. It is also possible to use the starting value (2 mod M p)(3 mod M p) −1, usually denoted by 2/3 for short. [2]
Using repeated squaring, the running time of this algorithm is O(k n 3), for an n-digit number, and k is the number of rounds performed; thus this is an efficient, polynomial-time algorithm. FFT-based multiplication, for example the Schönhage–Strassen algorithm, can decrease the running time to O(k n 2 log n log log n) = Õ(k n 2).
We continue recursively in this manner until we reach a number known to be prime, such as 2. We end up with a tree of prime numbers, each associated with a witness a. For example, here is a complete Pratt certificate for the number 229: 229 (a = 6, 229 − 1 = 2 2 × 3 × 19), 2 (known prime), 3 (a = 2, 3 − 1 = 2), 2 (known prime),
use the complex multiplication method to construct the curve E and a point P on it. Then we can use our proposition to verify the primality of N. Note that if m does not have a large prime factor or cannot be factored quickly enough, another choice of D can be made. [1]
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