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Explanation: Molar mass of. Mg = 24.3 g/mol. Cl = 35.5 g/mol. Molar mass of MgCl2 = 24.3 g/mol + (2 × 35.5 g/mol) = 95.2 g/mol. Answer link.
A solid mixture contains MgCl2 (molar mass = 95.218 g/mol) and NaCl (molar mass = 58.443 g/mol). When 0.5000 g of this solid is dissolved in enough water to form 1.000 L of solution, the osmotic pressure at 25.0 oC is observed to be 0.3950 atm. What is the mass percent of MgCl2 in the solid? (Assume ideal behavior for the solution.)
To find the number of moles in 0.684g of MgCl2, you need to divide the mass by the molar mass of MgCl2. The molar mass of MgCl2 is 95.211 g/mol (24.305 g/mol for Mg and 35.453 g/mol for Cl).
The molar mass of magnesium chloride is 95,205 g. The formula mass for MgCl2 (magnesium chloride) is calculated by adding the atomic masses of magnesium (Mg) and chlorine (Cl). The Atomic Mass of ...
The percent composition of "Mg" in "MgCl"_2" is "25.529%". The correct formula for magnesium chloride is "MgCl"_2". To determine the percent composition of "Mg", divide the molar mass of "Mg" by the molar mass of "MgCl"_2" and multiply by 100%.
A: Given : Mass of mixture = 0.8830 g And mass of AgCl produced = 1.913 g Molar mass of AgCl = Atomic… Q: Zinc and magnesium react with hydrochloric acid to produce the metal chlorides and hydrogen gas.
"860 g MgCl"_2 For starters, we know that a "1-M" solution contains 1 mole of solute for every "1.0 L" of solution. This implies that a "4.5-M" magnesium chloride solution will contain 4.5 moles of magnesium chloride, the solute, for every "1.0 L" of solution. So all you have to do now is figure out how many moles of magnesium chloride would be equivalent in "2.0 L" of solution to 4.5 moles in ...
Mg(s) + 2HCl(aq) rarr MgCl_2(aq) + H_2(g)uarr Moles of metal, = (4.86*g)/(24.305*g*mol^-1) = 0.200 mol. Moles of HCl = 100 *cm^-3xx2.00*mol*dm^-3 = 0.200 mol Clearly, the acid is in deficiency ; i.e. it is the limiting reagent, because the equation above specifies that that 2 equiv of HCl are required for each equiv of metal. So if 0.200 mol acid react, then (by the stoichiometry), 1/2 this ...
Science. Chemistry. Exactly 6.21 g of MgCl2 (molar mass = 95.2 g/mol) was dissolved in water. An analysis indicated that the molarity of the solution was 0.320 M. What was the volume (in mL) of the solution?
First find the atomic weight of the molecule. Mg = 24.312. Cl = 35.453 x 2 = 70.906. MgCl2 = 95.218 g/mol. Then multiply the given moles by the atomic weight of the molecule to get the mass. 9.40 ...