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  2. Parabola - Wikipedia

    en.wikipedia.org/wiki/Parabola

    The area A of the parabolic segment enclosed by the parabola and the chord is therefore =. This formula can be compared with the area of a triangle: ⁠ 1 / 2 ⁠ bh. In general, the enclosed area can be calculated as follows. First, locate the point on the parabola where its slope equals that of the chord.

  3. Quadrature of the Parabola - Wikipedia

    en.wikipedia.org/wiki/Quadrature_of_the_Parabola

    A parabolic segment is the region bounded by a parabola and line. To find the area of a parabolic segment, Archimedes considers a certain inscribed triangle. The base of this triangle is the given chord of the parabola, and the third vertex is the point on the parabola such that the tangent to the parabola at that point is parallel to the chord.

  4. Limaçon - Wikipedia

    en.wikipedia.org/wiki/Limaçon

    Construction of the limaçon r = 2 + cos(π – θ) with polar coordinates' origin at (x, y) = (⁠ 1 / 2 ⁠, 0). In geometry, a limaçon or limacon / ˈ l ɪ m ə s ɒ n /, also known as a limaçon of Pascal or Pascal's Snail, is defined as a roulette curve formed by the path of a point fixed to a circle when that circle rolls around the outside of a circle of equal radius.

  5. Geometric series - Wikipedia

    en.wikipedia.org/wiki/Geometric_series

    Archimedes in his The Quadrature of the Parabola used the sum of a geometric series to compute the area enclosed by a parabola and a straight line. Archimedes' theorem states that the total area under the parabola is ⁠ 4 / 3 ⁠ of the area of the blue triangle. His method was to dissect the area into infinite triangles as shown in the ...

  6. Archimedes - Wikipedia

    en.wikipedia.org/wiki/Archimedes

    In Quadrature of the Parabola, Archimedes proved that the area enclosed by a parabola and a straight line is ⁠ 4 / 3 ⁠ times the area of a corresponding inscribed triangle as shown in the figure at right. He expressed the solution to the problem as an infinite geometric series with the common ratio ⁠ 1 / 4 ⁠:

  7. Lemniscate of Bernoulli - Wikipedia

    en.wikipedia.org/wiki/Lemniscate_of_Bernoulli

    The area enclosed by the lemniscate is a 2 = 2c 2. The lemniscate is the circle inversion of a hyperbola and vice versa. The two tangents at the midpoint O are perpendicular, and each of them forms an angle of ⁠ π / 4 ⁠ with the line connecting F 1 and F 2. The planar cross-section of a standard torus tangent to its inner equator is a ...

  8. Circular segment - Wikipedia

    en.wikipedia.org/wiki/Circular_segment

    A circular segment (in green) is enclosed between a secant/chord (the dashed line) and the arc whose endpoints equal the chord's (the arc shown above the green area). In geometry, a circular segment or disk segment (symbol: ⌓) is a region of a disk [1] which is "cut off" from the rest of the disk by a straight line.

  9. Paraboloid - Wikipedia

    en.wikipedia.org/wiki/Paraboloid

    In this position, the hyperbolic paraboloid opens downward along the x-axis and upward along the y-axis (that is, the parabola in the plane x = 0 opens upward and the parabola in the plane y = 0 opens downward). Any paraboloid (elliptic or hyperbolic) is a translation surface, as it can be generated by a moving parabola directed by a second ...