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  2. Parabola - Wikipedia

    en.wikipedia.org/wiki/Parabola

    The area A of the parabolic segment enclosed by the parabola and the chord is therefore =. This formula can be compared with the area of a triangle: ⁠ 1 / 2 ⁠ bh. In general, the enclosed area can be calculated as follows. First, locate the point on the parabola where its slope equals that of the chord.

  3. Quadrature of the Parabola - Wikipedia

    en.wikipedia.org/wiki/Quadrature_of_the_Parabola

    A parabolic segment is the region bounded by a parabola and line. To find the area of a parabolic segment, Archimedes considers a certain inscribed triangle. The base of this triangle is the given chord of the parabola, and the third vertex is the point on the parabola such that the tangent to the parabola at that point is parallel to the chord.

  4. Lemniscate of Bernoulli - Wikipedia

    en.wikipedia.org/wiki/Lemniscate_of_Bernoulli

    The area enclosed by the lemniscate is a 2 = 2c 2. The lemniscate is the circle inversion of a hyperbola and vice versa. The two tangents at the midpoint O are perpendicular, and each of them forms an angle of ⁠ π / 4 ⁠ with the line connecting F 1 and F 2. The planar cross-section of a standard torus tangent to its inner equator is a ...

  5. Archimedes - Wikipedia

    en.wikipedia.org/wiki/Archimedes

    In Quadrature of the Parabola, Archimedes proved that the area enclosed by a parabola and a straight line is ⁠ 4 / 3 ⁠ times the area of a corresponding inscribed triangle as shown in the figure at right. He expressed the solution to the problem as an infinite geometric series with the common ratio ⁠ 1 / 4 ⁠:

  6. Quadrature (geometry) - Wikipedia

    en.wikipedia.org/wiki/Quadrature_(geometry)

    The area of the surface of a sphere is equal to four times the area of the circle formed by a great circle of this sphere. The area of a segment of a parabola determined by a straight line cutting it is 4/3 the area of a triangle inscribed in this segment. For the proofs of these results, Archimedes used the method of exhaustion attributed to ...

  7. Parabolic coordinates - Wikipedia

    en.wikipedia.org/wiki/Parabolic_coordinates

    The scale factors for the parabolic coordinates (,) are equal = = + Hence, the infinitesimal element of area is = (+) and the Laplacian equals = + (+) Other differential operators such as and can be expressed in the coordinates (,) by substituting the scale factors into the general formulae found in orthogonal coordinates.

  8. Paraboloid - Wikipedia

    en.wikipedia.org/wiki/Paraboloid

    In this position, the hyperbolic paraboloid opens downward along the x-axis and upward along the y-axis (that is, the parabola in the plane x = 0 opens upward and the parabola in the plane y = 0 opens downward). Any paraboloid (elliptic or hyperbolic) is a translation surface, as it can be generated by a moving parabola directed by a second ...

  9. Area - Wikipedia

    en.wikipedia.org/wiki/Area

    The formula for the area of a circle (more properly called the area enclosed by a circle or the area of a disk) is based on a similar method. Given a circle of radius r, it is possible to partition the circle into sectors, as shown in the figure to the right. Each sector is approximately triangular in shape, and the sectors can be rearranged to ...