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  2. Poundal - Wikipedia

    en.wikipedia.org/wiki/Poundal

    Since a pound of force (pound force) accelerates a pound of mass at 32.174 049 ft/s 2 (9.80665 m/s 2; the acceleration of gravity, g), we can scale down the unit of force to compensate, giving us one that accelerates 1 pound mass at 1 ft/s 2 rather than at 32.174 049 ft/s 2; and that is the poundal, which is approximately 1 ⁄ 32 pound force.

  3. Gravitational acceleration - Wikipedia

    en.wikipedia.org/wiki/Gravitational_acceleration

    [2] [3] At different points on Earth's surface, the free fall acceleration ranges from 9.764 to 9.834 m/s 2 (32.03 to 32.26 ft/s 2), [4] depending on altitude, latitude, and longitude. A conventional standard value is defined exactly as 9.80665 m/s² (about 32.1740 ft/s²).

  4. Foot per second squared - Wikipedia

    en.wikipedia.org/wiki/Foot_per_second_squared

    The foot per second squared (plural feet per second squared) is a unit of acceleration. [1] It expresses change in velocity expressed in units of feet per second (ft/s) divided by time in seconds (s) (or the distance in feet (ft) traveled or displaced, divided by the time in seconds (s) squared).

  5. Gravity of Earth - Wikipedia

    en.wikipedia.org/wiki/Gravity_of_Earth

    In SI units, this acceleration is expressed in metres per second squared (in symbols, m/s 2 or m·s −2) or equivalently in newtons per kilogram (N/kg or N·kg −1). Near Earth's surface, the acceleration due to gravity, accurate to 2 significant figures, is 9.8 m/s 2 (32 ft/s 2).

  6. Standard gravity - Wikipedia

    en.wikipedia.org/wiki/Standard_gravity

    The standard acceleration of gravity or standard acceleration of free fall, often called simply standard gravity and denoted by ɡ 0 or ɡ n, is the nominal gravitational acceleration of an object in a vacuum near the surface of the Earth. It is a constant defined by standard as 9.806 65 m/s 2 (about 32.174 05 ft/s 2).

  7. Equations for a falling body - Wikipedia

    en.wikipedia.org/wiki/Equations_for_a_falling_body

    Near the surface of the Earth, the acceleration due to gravity g = 9.807 m/s 2 (metres per second squared, which might be thought of as "metres per second, per second"; or 32.18 ft/s 2 as "feet per second per second") approximately. A coherent set of units for g, d, t and v is essential.

  8. Pound (force) - Wikipedia

    en.wikipedia.org/wiki/Pound_(force)

    The pound-force is the product of one avoirdupois pound (exactly 0.45359237 kg) and the standard acceleration due to gravity, approximately 32.174049 ft/s 2 (9.80665 m/s 2). [ 5 ] [ 6 ] [ 7 ] The standard values of acceleration of the standard gravitational field ( g n ) and the international avoirdupois pound (lb) result in a pound-force equal ...

  9. Physical geodesy - Wikipedia

    en.wikipedia.org/wiki/Physical_geodesy

    Near Earth's surface, the acceleration due to gravity, accurate to 2 significant figures, is 9.8 m/s 2 (32 ft/s 2). This means that, ignoring the effects of air resistance, the speed of an object falling freely will increase by about 9.8 metres per second (32 ft/s) every second.