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Multiplying polynomials [ edit ] When using algebra tiles to multiply a monomial by a monomial , the student must first set up a rectangle where the length of the rectangle is the one monomial and then the width of the rectangle is the other monomial , similar to when one multiplies integers using algebra tiles.
The template to the right includes links to alphabetical lists of all mathematical articles. This article brings together the same content organized in a manner better suited for browsing. Lists cover aspects of basic and advanced mathematics, methodology, mathematical statements, integrals, general concepts, mathematical objects, and reference ...
A function f : A n → A 1 is said to be polynomial (or regular) if it can be written as a polynomial, that is, if there is a polynomial p in k[x 1,...,x n] such that f(M) = p(t 1,...,t n) for every point M with coordinates (t 1,...,t n) in A n. The property of a function to be polynomial (or regular) does not depend on the choice of a ...
An algebraic equation is an equation involving polynomials, for which algebraic expressions may be solutions. If you restrict your set of constants to be numbers, any algebraic expression can be called an arithmetic expression. However, algebraic expressions can be used on more abstract objects such as in Abstract algebra.
Algebraic operations in the solution to the quadratic equation.The radical sign √, denoting a square root, is equivalent to exponentiation to the power of 1 / 2 .The ± sign means the equation can be written with either a + or a – sign.
A visual memory tool can replace the FOIL mnemonic for a pair of polynomials with any number of terms. Make a table with the terms of the first polynomial on the left edge and the terms of the second on the top edge, then fill in the table with products of multiplication. The table equivalent to the FOIL rule looks like this:
In the mathematical study of polynomial splines the question of what happens when two knots, say t i and t i+1, are taken to approach one another and become coincident has an easy answer. The polynomial piece P i (t) disappears, and the pieces P i−1 (t) and P i+1 (t) join with the sum of the smoothness losses for t i and t i+1.