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  2. Addition - Wikipedia

    en.wikipedia.org/wiki/Addition

    Addition of fractions is much simpler when the denominators are the same; in this case, one can simply add the numerators while leaving the denominator the same: + = +, so + = + =. [ 63 ] The commutativity and associativity of rational addition is an easy consequence of the laws of integer arithmetic. [ 64 ]

  3. Lowest common denominator - Wikipedia

    en.wikipedia.org/wiki/Lowest_common_denominator

    In mathematics, the lowest common denominator or least common denominator (abbreviated LCD) is the lowest common multiple of the denominators of a set of fractions. It simplifies adding, subtracting, and comparing fractions.

  4. Fraction - Wikipedia

    en.wikipedia.org/wiki/Fraction

    A simple fraction (also known as a common fraction or vulgar fraction, where vulgar is Latin for "common") is a rational number written as a/b or ⁠ ⁠, where a and b are both integers. [9] As with other fractions, the denominator (b) cannot be zero. Examples include ⁠ 1 / 2 ⁠, − ⁠ 8 / 5 ⁠, ⁠ −8 / 5 ⁠, and ⁠ 8 / −5 ⁠

  5. Extraneous and missing solutions - Wikipedia

    en.wikipedia.org/wiki/Extraneous_and_missing...

    To begin solving, we multiply each side of the equation by the least common denominator of all the fractions contained in the equation. In this case, the least common denominator is () (+). After performing these operations, the fractions are eliminated, and the equation becomes:

  6. Math Blaster Episode I: In Search of Spot - Wikipedia

    en.wikipedia.org/wiki/Math_Blaster_Episode_I:_In...

    The user must identify the pattern to find the missing number (for example, if the problem presented is "5, 10, 15, _, 25", then the missing number is 20). Estimation - the user must round numbers to estimate the answer. Fractions/decimals/percents - the user must solve problems that involve fractions, decimals and percentages.

  7. Elementary arithmetic - Wikipedia

    en.wikipedia.org/wiki/Elementary_arithmetic

    A subtraction problem such as is solved by borrowing a 10 from the tens place to add to the ones place in order to facilitate the subtraction. Subtracting 9 from 6 involves borrowing a 10 from the tens place, making the problem into +. This is indicated by crossing out the 8, writing a 7 above it, and writing a 1 above the 6.