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Ammonium iodide is the inorganic compound with the formula NH 4 I. A white solid. It is an ionic compound, although impure samples appear yellow. This salt consists of ammonium cation and an iodide anion. [1] It can be prepared by the action of hydroiodic acid on ammonia. It is easily soluble in water, from which it crystallizes in cubes.
The iodide is regenerated, meaning the reaction runs with the iodide/hypoiodite as a catalyst in the presence of excess of the original strong oxidizing agent. Ammonium hypoiodites are capable of oxidizing benzylic methyl groups, [ 2 ] initiating oxidative dearomatization , [ 3 ] and oxidative decarboxylation of β-keto lactones . [ 4 ]
Using its low solubility in water, it can also be precipitated from an iodate solution with an ammonium salt. 2 KIO 3 + (NH 4) 2 SO 4 → 2 NH 4 IO 3 + K 2 SO 4. Unlike other iodates, ammonium iodate can't be prepared by dissolving iodine in an ammonium hydroxide solution, instead the highly explosive nitrogen triiodide is formed. 3 I 2 + 5 NH ...
This clock reaction uses sodium, potassium or ammonium persulfate to oxidize iodide ions to iodine. Sodium thiosulfate is used to reduce iodine back to iodide before the iodine can complex with the starch to form the characteristic blue-black color. Iodine is generated: 2 I − + S 2 O 2− 8 → I 2 + 2 SO 2− 4. And is then removed:
The enthalpy of formation Δ f H 0 of tetra-n-butylammonium iodide is −499 kJ/mol, which is lower than that for the bromide or chloride (−540, −564 kJ/mol). [2] At lower temperatures with water tetra-n-butylammonium iodide forms a clathrate hydrate. [2] The tetra-n-butylammonium cation is large and hydrophobic.
Tetraethylammonium iodide is a quaternary ammonium compound with the chemical formula C 8 H 20 N + I −. It has been used as the source of tetraethylammonium ions in pharmacological and physiological studies, but is also used in organic chemical synthesis.
The octanol-water partition coefficient of TMA iodide, P o-w, is 1.2 × 10 −4 (or log P ≈ −3.92). [7] In the TMA cation, the methyl groups are tetrahedrally arranged around the central N atom, as is evident from X-ray crystallographic studies of various of its salts.
Cerium diiodide can be obtained from the reduction of cerium(III) iodide with metallic cerium under vacuum at 800 °C to 900 °C. [2] Ce + 2 CeI 3 → CeI 2. It can also be formed from the reaction of cerium and ammonium iodide in liquid ammonia at −78 °C. The reaction forms an ammonia complex of cerium diiodide, which decomposes to cerium ...