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United States Senate election in New York, 1839/1840; 1840 and 1841 United States Senate elections; See also. Category:1840 elections
The 1840 United States presidential election in New York took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose 42 representatives, or electors to the Electoral College , who voted for President and Vice President .
At the state election in November 1837, 101 Whigs and 27 Democrats were elected to the assembly, and 6 Whigs and 2 Democrats were elected to the state senate. At the 1838 state election, 82 Whigs and 46 Democrats were elected to the assembly, and 5 Whigs and 3 Democrats to the state senate. This added up to 18 Democrats and 14 Whigs in the ...
Democratic members of the New Hampshire General Court made a call for the 1840 Democratic National Convention which was held in Baltimore, Maryland in May 1840. Delegates from twenty-two states attended the convention, but the sizes of the delegations varied with New Jersey having fifty-nine delegates to cast its eight votes while Massachusetts only had one delegate to cast its fourteen votes.
Pages in category "1840 New York (state) elections" The following 4 pages are in this category, out of 4 total. ... 1839–1840 United States Senate election in New York
The 1855 to 1875 New York state censuses asked the person for the name of the county that one was born in if one was born in New York State. [15] Also, the 1865 New York state census asked many questions about military service. [15] New York did not conduct a census in 1885 because its Governor David B. Hill refused to support the proposed ...
The 1840 New York gubernatorial election was held from November 2 to 4, 1840, to elect the Governor and Lieutenant Governor of New York. General election [ edit ]
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