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2. SQL subquery with COUNT help - Stack Overflow

   stackoverflow.com/questions/3884733

   85. This is probably the easiest way, not the prettiest though: SELECT *, (SELECT Count(*) FROM eventsTable WHERE columnName = 'Business') as RowCount. FROM eventsTable. WHERE columnName = 'Business'. This will also work without having to use a group by.

3. sql server - SQL Query subquery with COUNT() - Stack Overflow

   stackoverflow.com/questions/62369338

   The subquery is not related to the outer query. So, either all rows are returned (if the subquery returns any rows) or no rows are returned. You can fix this with a correlated subquery. However window functions are faster and simpler to query: SELECT c.*. FROM (SELECT c.*, COUNT(*) OVER (PARTITION BY conm) as cnt. FROM combinedata1 c.

4. SUM of grouped COUNT in SQL Query - Stack Overflow

   stackoverflow.com/questions/12927268

   4. If you need the sum in the select itself to calculate with it, use a subselect: SELECT Name, COUNT(*) AS amount, COUNT(*)/total.total * 100 AS percentage, total.total FROM temp, ( SELECT COUNT(*) AS total FROM temp ) AS total GROUP BY Name See SQLfiddle. – yunzen.

5. Find out how many times a regex matches in a string in Python

   stackoverflow.com/questions/1374457

   return re.subn(pattern, '', thestring)[1] the only real advantage of this latter idea would come if you only cared to count (say) up to 100 matches; then, re.subn(pattern, '', thestring, 100)[1] might be practical (returning 100 whether there are 100 matches, or 1000, or even larger numbers). Counting overlapping matches requires you to write ...

6. Subquery count () for postgres query - Stack Overflow

   stackoverflow.com/questions/53662604

   Aggregate the data in a derived table (a subquery in FROM clause):. select a.ip, a.latitude, a.longitude, st_SetSrid(ST_MAKEPOINT(a.longitude, a.latitude), 4326) as geom, c.count, l.referrer from squarespace_ip_addresses a left join squarespace_logs l on a.ip = l.hostname left join ( select hostname, count(*) from squarespace_logs group by hostname ) c on a.ip = c.hostname

7. How do I use Count on a Sub-Query? - Stack Overflow

   stackoverflow.com/questions/3478630

   I've got a MySQL statement that selects a name and also makes a ranking. SELECT t.name, (SELECT COUNT(*) FROM my_table1 z WHERE z.type LI...

8. Count number of occurrences of a substring in a string

   stackoverflow.com/questions/8899905

   def substr_count(st, sub): # If a non-overlapping substring then just # use the standard string `count` method # to count the substring occurences if sub[0] != sub[-1]: return st.count(sub) # Otherwise, create a copy of the source string, # and starting from the index of the first occurence # of the substring, adjust the source string to start ...

9. How to count string occurrence in string? - Stack Overflow

   stackoverflow.com/questions/4009756

   5. A simple way would be to split the string on the required word, the word for which we want to calculate the number of occurences, and subtract 1 from the number of parts: function checkOccurences(string, word) {. return string.split(word).length - 1;

10. Powershell - List subdirectories and count files per subdirectory

    stackoverflow.com/questions/26320441

    I removed the -Recurse of the file count since that could be misleading. Put it back if it suits you better. Put it back if it suits you better. The final Select-Object is to ensure the order of the output which is an object now that you could sort or do whatever you wanted with.

11. Easiest way to get a total count and a count of a subset?

    stackoverflow.com/questions/4414539

    You could use a CTE: SELECT DATEPART(WEEKDAY,start_date) AS weekday. FROM attend. WHERE empl_no = 12345. (SELECT COUNT(*) FROM T1) AS total, (SELECT COUNT(*) FROM T1 WHERE weekday = 2 OR weekday = 6) AS subset. Not hitting the attend table twice should help with performance especially if your query involved other tables.