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2. What is the difference between signed and unsigned int

   stackoverflow.com/questions/5739888

   97. In laymen's terms an unsigned int is an integer that can not be negative and thus has a higher range of positive values that it can assume. A signed int is an integer that can be negative but has a lower positive range in exchange for more negative values it can assume. answered Jun 29, 2015 at 4:58.

3. Comparison operation on unsigned and signed integers

   stackoverflow.com/questions/2084949

   In your case the "common" type is unsigned int. This means that int operand (your b) will get converted to unsigned int before the comparison, as well as for the purpose of performing subtraction. When -1 is converted to unsigned int the result is the maximal possible unsigned int value (same as UINT_MAX).

4. Convert unsigned int to signed int C - Stack Overflow

   stackoverflow.com/questions/8317295

   Note that there is no fully C-compliant way to do this because casting between signed/unsigned for values out of range is implementation-defined. But this will still work in most cases: unsigned int x = 65529; int y = (short) x; // If short is a 16-bit integer. or alternatively: unsigned int x = 65529; int y = (int16_t) x; // This is defined in ...

5. What is the difference between signed and unsigned variables?

   stackoverflow.com/questions/621290

   Unsigned and signed variables of the same type (such as int and byte) both have the same range (range of 65,536 and 256 numbers, respectively), but unsigned can represent a larger magnitude number than the corresponding signed variable. For example, an unsigned byte can represent values from 0 to 255, while signed byte can represent -128 to 127 ...

6. Verilog signed vs unsigned samples and first - Stack Overflow

   stackoverflow.com/questions/24162329

   In Verilog a reg contains binary data, signed unsigned are just a matter of interpretation. The bit values stay the same, subtraction and addition are always performed using two's complement. For example, we can look at a 4 bit value and see how the numbers can be interpreted: Binary Unsigned signed. 1000 8 -8.

7. Signed versus Unsigned Integers - Stack Overflow

   stackoverflow.com/questions/247873

   447. Am I correct to say the difference between a signed and unsigned integer is: Unsigned can hold a larger positive value and no negative value. Unsigned uses the leading bit as a part of the value, while the signed version uses the left-most-bit to identify if the number is positive or negative. Signed integers can hold both positive and ...

8. Convert signed to unsigned integer mathematically

   stackoverflow.com/questions/29811702

   3. Mathematically, the conversion from signed to unsigned works as follows: (1) do the integer division of the signed integer by 1 + max, (2) codify the signed integer as the non-negative remainder of the division. Here max is the maximum integer you can write with the available number of bits, 16 in your case.

9. What is the difference between signed and unsigned binary

   stackoverflow.com/questions/42603639

   5. A "signed" variable means that the value holds a positive or negative value using it's most significant bit (the last bit to the left), which is what we call the "signed bit". An "unsigned" variable does not, but instead the most significant bit is just the next power of two. We call a signed bit that is 1 a negative number whereas on an ...

10. c - Arithmetic bit-shift on a signed integer - Stack Overflow

    stackoverflow.com/questions/4009885

    If your 8 bits are meant to represent a signed 8 bit value (as you're talking about a "signed 32 bit integer" before switching to 8 bit examples) then you have a negative number. Shifting it right may fill "empty" bits with the original MSB (i.e. perform sign extension) or it may shift in zeroes, depending on platform and/or compiler.

11. How to safely convert unsigned value to signed? - Stack Overflow

    stackoverflow.com/questions/18645197

    Conversion from unsigned to signed is not undefined, but implementation defined. From C++ Standard, chapter 4.7 Integral conversions, paragraph 3: If the destination type is signed, the value is unchanged if it can be represented in the destination type (and bit-field width); otherwise, the value is implementation-defined