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Since the velocity of the object is the derivative of the position graph, the area under the line in the velocity vs. time graph is the displacement of the object. (Velocity is on the y-axis and time on the x-axis. Multiplying the velocity by the time, the time cancels out, and only displacement remains.)
Date/Time Thumbnail Dimensions User Comment; current: 01:22, 25 February 2007: 496 × 504 (111 KB) Stannered {{Information |Description=Example of a en:velocity vs. time graph, and the relationship between velocity v, en:displacement s, and en:acceleration a. Traced in en:Inkscape from an original drawn in en:Microsoft Paint. |Source=[[:
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Intuitively, the velocity increases linearly, so the average velocity multiplied by time is the distance traveled while increasing the velocity from v 0 to v, as can be illustrated graphically by plotting velocity against time as a straight line graph. Algebraically, it follows from solving [1] for
Printable version; Page information; Get shortened URL ... Graph of the velocity versus time of a skydiver reaching terminal velocity. The time evolution is given by
These relationships can be demonstrated graphically. The gradient of a line on a displacement time graph represents the velocity. The gradient of the velocity time graph gives the acceleration while the area under the velocity time graph gives the displacement. The area under a graph of acceleration versus time is equal to the change in velocity.
In physics, motion is when an object changes its position with respect to a reference point in a given time. Motion is mathematically described in terms of displacement, distance, velocity, acceleration, speed, and frame of reference to an observer