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That's correct but it can be simplified to "I produced 1 MW continuously (or average) for two hours so MW × hours = 2 MWh. If in 15 mins, it would be (1x24)/4 = 6 MWh. No, you're mixing power and energy again. It's just average power × time. 1 MW for 2 hours = 2 MWh.
MW is MegaWatt and MWh is MegaWatt hour. MW is a unit of power and MWh is a unit of energy. Taking the Brisbane example... 2.2 MWh is the installed battery capacity which can energise the installed 1.1 MW load for 2 hours.
Power is energy per time. This also means that energy can be expressed as power times time, like the kiloWatt-hours used to express the electric energy your house consumes during a billing period. Another common measure of energy is the Joule. A Watt (a unit of power) is one Joule per second. A kiloWatt-hour is therefore 3.6 MJ.
4. "MWh/h is a unit of AVERAGE power during a certain period" So is MW. "so it is used to show ENERGY consumption" No. MWh/h is a measure of power, not energy. – endolith. Jan 4, 2016 at 17:14. 1. It is strange that this answer was accepted. MWh/h is silly, as the ‘h’ in the denominator is arbitrary.
So what does 200 MW capacity power plant mean w.r.t. time? See this answer for a different explanation. rate of energy generation or consumption. 200 MW = 200 MJ/s = 200, 000, 000 J/s 200 MW 200 MJ/s 200 000 000 J/s. 200 MJ 200 MJ 200 MJ × 10 s = 2000 MJ = 2 GJ 200 MJ 10 s 2000 MJ 2 GJ.
Now see the units, mAh (Milli ampere-hours) It means if the voltage is constant then we can measure the capacity in watt-hours. At homes, where voltage is constant we measure the capacity in Power. In laptops or mobiles, These devices use a battery's energy according to usage, It drains faster if you are playing PUBG (games) else it drains slower.
2. I have metering data (kW) in 15 minute intervals that I am trying to get a monthly kWh total for... I simply summed the entire kW range, then multiplied it by hours in the month 745 (total number of readings 2,981/4). This seemed too simple though and now I'm just confused after looking at it for so long.
1 1 1. Compute battery Watt hours (Amp hour capacity * nominal pack voltage). Then divide the result by the average power consumption of the car, in Watts. The result is the battery life, in hours. So it is: watt-hours / watts = hours. The motor max power does not matter. You need to know the actual average power consumption of everything ...
1000 billion units (kWh) = 10^12 kWh over 8000 hours (a very approximate year!) gives us a mean demand of 10^12/8 W = 120GW. Demand will be lower at night and higher during the day - say, 80GW and 160GW respectively. Therefore there is enough solar capacity alone to exceed likely daytime demand during (probably rare) peak solar periods.
So 11200 MWh equals 2800MW for 4 hours, or 5600MW for 2 hours, or 1 MW for 11200 hours. I assume that's the theoretical ballpark calculation you're looking for. Now, if you are to actually build a storage plant of 11200 MWh you'll want to be a lot more sure about the details, like efficiency, and maximum discharge rate. \$\endgroup\$