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1,1-Diethoxyethane (acetaldehyde diethyl acetal) is a major flavoring component of distilled beverages, especially malt whisky [3] and sherry. [4] Although it is just one of many compounds containing an acetal functional group, this specific chemical is sometimes called simply acetal .
Conversion of acetaldehyde to 1,1-diethoxyethane, R 1 = CH 3 R 2 = CH 3 CH 2. Acetaldehyde forms a stable acetal upon reaction with ethanol under conditions that favor dehydration. The product, CH 3 CH(OCH 2 CH 3) 2, is formally named 1,1-diethoxyethane but is commonly referred to as "acetal". [39]
1,1-Diethoxyethane (acetaldehyde diethyl acetal), sometimes called simply "acetal", is an important flavouring compound in distilled beverages. [6] Two ketals of ethyl acetoacetate are used in commercial fragrances. [ 7 ]
This page contains tables of azeotrope data for various binary and ternary mixtures of solvents. The data include the composition of a mixture by weight (in binary azeotropes, when only one fraction is given, it is the fraction of the second component), the boiling point (b.p.) of a component, the boiling point of a mixture, and the specific gravity of the mixture.
133.191 g·mol −1 Appearance colorless liquid Density: 0.9152 g/cm 3: Melting point: −78 °C (−108 °F; 195 K) Boiling point: 163 °C (325 °F; 436 K)
2,2-Dimethoxypropane (DMP) is an organic compound with the formula (CH 3) 2 C(OCH 3) 2.A colorless liquid, it is the product of the condensation of acetone and methanol.DMP is used as a water scavenger in water-sensitive reactions.
Phenylacetaldehyde is an organic compound used in the synthesis of fragrances and polymers. [1] Phenylacetaldehyde is an aldehyde that consists of acetaldehyde bearing a phenyl substituent; the parent member of the phenylacetaldehyde class of compounds.
Because acetic anhydride is not stable in water, the conversion is conducted under anhydrous conditions. To a decreasing extent, acetic anhydride is also prepared by the reaction of ketene with acetic acid at 45–55 °C and low pressure (0.05–0.2 bar). [8] H 2 C=C=O + CH 3 COOH → (CH 3 CO) 2 O (ΔH = −63 kJ/mol)