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Anhydrous SnCl 2 is prepared by the action of dry hydrogen chloride gas on tin metal. The dihydrate is made by a similar reaction, using hydrochloric acid: Sn (s) + 2 HCl (aq) → SnCl 2 (aq) + H 2 (g) The water then carefully evaporated from the acidic solution to produce crystals of SnCl 2 ·2H 2 O.
Anhydrous tin(IV) chloride is a major precursor in organotin chemistry. Upon treatment with Grignard reagents, tin(IV) chloride gives tetraalkyltin compounds: [5] SnCl 4 + 4 RMgCl → SnR 4 + 4 MgCl 2. Anhydrous tin(IV) chloride reacts with tetraorganotin compounds in redistribution reactions: SnCl 4 + SnR 4 → 2 SnCl 2 R 2
CoCl 2 ·6H 2 O – cobalt(II) chloride hexahydrate; SnCl 2 ·2H 2 O – tin(II) (or stannous) chloride dihydrate; For many salts, the exact bonding of the water is unimportant because the water molecules are made labile upon dissolution. For example, an aqueous solution prepared from CuSO 4 ·5H 2 O and anhydrous CuSO 4 behave identically.
Cobalt(II) chloride is an inorganic compound, a salt of cobalt and chlorine, with the formula CoCl 2.The compound forms several hydrates CoCl 2 ·n H 2 O, for n = 1, 2, 6, and 9. . Claims of the formation of tri- and tetrahydrates have not been confirmed
Neodymium(III) chloride or neodymium trichloride is a chemical compound of neodymium and chlorine with the formula NdCl 3.This anhydrous compound is a mauve-colored solid that rapidly absorbs water on exposure to air to form a purple-colored hexahydrate, NdCl 3 ·6H 2 O. Neodymium(III) chloride is produced from minerals monazite and bastnäsite using a complex multistage extraction process.
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Tin(IV) nitrate reacts with trifloroacetic acid anhydride to yield (NO 2 +) 2 [Sn(OOCCF 3) 6 2−] which is a nitronium salt. With trifluoroacetic acid a similar compound solvated with trifluoroacetic acid is produced. [6] It also reacts with acetic anhydride or acetic acid to produce tin(IV) acetate and with nitric oxide to produce tin(IV ...