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The "optimal viewing distance" [5] is based on the limits of the human eye, ... (equivalent to about 1.6264 times the screen size in a 16:9 TV).
At this distance, the individual pixels cannot be resolved while simultaneously maximizing the viewing area. For more TV resolutions, see "The optimal viewing distance". [3] [4] The TV image is composed of many lines of pixels. Ideally, the TV watcher sits far enough away from the screen that the individual lines merge into one solid image.
However, this optimal distance has the characteristic of being objective and simple to implement. The latest version of the ITU BT.500 uses it: "The design viewing distance (DVD), or optimal viewing distance, for a digital system is the distance at which two adjacent pixels subtend an angle of 1 arc-min at the viewer's eye". The TABLE 1-1 :
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As the display size increases so does the ideal viewing distance. Bernard J. Lechner, while working for RCA, studied the best viewing distances for various conditions and derived the so-called Lechner distance. As a rule of thumb, the viewing distance should be roughly two to three times the screen size for standard definition (SD) displays.
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For example, the optimal viewing distance for a 42 inches (110 cm) Full HD TV (1080p) is 5.5 feet (170 cm). Lechner researched the typical distance between a viewer and their television screen by taking measurements in many American homes. The median distance compiled from all his data came out to 9 feet (2.7 m).