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F is the resultant force applied, t 1 and t 2 are times when the impulse begins and ends, respectively, m is the mass of the object, v 2 is the final velocity of the object at the end of the time interval, and; v 1 is the initial velocity of the object when the time interval begins. Impulse has the same units and dimensions (MLT −1) as momentum.
The scalar product of a force F and the velocity v of its point of application defines the power input to a system at an instant of time. Integration of this power over the trajectory of the point of application, C = x ( t ) , defines the work input to the system by the force.
Power is the rate with respect to time at which work is done; it is the time derivative of work: =, where P is power, W is work, and t is time. We will now show that the mechanical power generated by a force F on a body moving at the velocity v can be expressed as the product: P = d W d t = F ⋅ v {\displaystyle P={\frac {dW}{dt}}=\mathbf {F ...
The kilogram-force leads to an alternate, but rarely used unit of mass: the metric slug (sometimes mug or hyl) is that mass that accelerates at 1 m·s −2 when subjected to a force of 1 kgf. The kilogram-force is not a part of the modern SI system, and is generally deprecated, sometimes used for expressing aircraft weight, jet thrust, bicycle ...
F 21 is the force applied on body 2 exerted by body 1, G is the gravitational constant, m 1 and m 2 are respectively the masses of bodies 1 and 2, r 21 = r 2 − r 1 is the displacement vector between bodies 1 and 2, and
At any instant of time, the net force on a body is equal to the body's acceleration multiplied by its mass or, equivalently, the rate at which the body's momentum is changing with time. If two bodies exert forces on each other, these forces have the same magnitude but opposite directions. [1] [2]
The gravitational field g (also called gravitational acceleration) is a vector field – a vector at each point of space (and time).It is defined so that the gravitational force experienced by a particle is equal to the mass of the particle multiplied by the gravitational field at that point.
In the image, the vector F 1 is the force experienced by q 1, and the vector F 2 is the force experienced by q 2. When q 1 q 2 > 0 the forces are repulsive (as in the image) and when q 1 q 2 < 0 the forces are attractive (opposite to the image). The magnitude of the forces will always be equal.