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For example, reaction of aniline with sulfuric acid at 180 °C produces sulfanilic acid, H 2 NC 6 H 4 SO 3 H. If bromine water is added to aniline, the bromine water is decolourised and a white precipitate of 2,4,6-tribromoaniline is formed. To generate the mono-substituted product, a protection with acetyl chloride is required:
A white solid, it is the chloride salt of anilinium, which is the conjugate acid of aniline, C 6 H 5 NH 2. Anilinium chloride is produced by treatment of aniline with hydrochloric acid. The cation consists of a phenyl ring attached to a tetrahedral ammonium center. The C-N bond elongates from 1.41 Å in aniline to 1.474 Å in anilinium. [2]
For aqueous solutions of an acid HA, the base is water; the conjugate base is A − and the conjugate acid is the hydronium ion. The Brønsted–Lowry definition applies to other solvents, such as dimethyl sulfoxide : the solvent S acts as a base, accepting a proton and forming the conjugate acid SH + .
2,4,6-Tribromoaniline can be prepared by treating bromine water with aniline in a solution of acetic acid or dilute hydrochloric acid: [1] By reacting bromine with aniline in water, a white precipitate immediately forms and that is 2,4,6-tribromoaniline
The same equation relating the concentrations of acid and base applies. The concept of neutralization is not limited to reactions in solution. For example, the reaction of limestone with acid such as sulfuric acid is also a neutralization reaction. [Ca,Mg]CO 3 (s) + H 2 SO 4 (aq) → (Ca 2+, Mg 2+)(aq) + SO 2− 4 (aq) + CO 2 (g) + H 2 O
Dimethylaniline undergoes many of the reactions expected for an aniline, being weakly basic and reactive toward electrophiles. [6] It is nitrated to produce tetryl, a derivative with four nitro groups which was once used as explosive. In acidic solution, the initial nitration gives 3-nitrodimethylaniline. [7]
The hydrochloric acid and sodium hydroxide byproducts undergo a secondary reaction to release the byproducts of water and sodium chloride. The overall reaction is thus NaOCl + 2NH 3 → N 2 H 4 + NaCl + H 2 O. Excess ammonia and sodium chloride are removed by distillation, followed by azeotropic distillation with aniline to remove water.
The sodium fusion extract is made alkaline by adding NaOH. To this mixture, freshly prepared FeSO 4 solution is added and boiled for some time and then cooled. A few drops of FeCl 3 are added and Prussian blue (bluish green) color forms due to formation of ferric ferrocyanide along with NaCl. This shows the presence of nitrogen in the organic ...