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The first equation shows that, after one second, an object will have fallen a distance of 1/2 × 9.8 × 1 2 = 4.9 m. After two seconds it will have fallen 1/2 × 9.8 × 2 2 = 19.6 m; and so on. On the other hand, the penultimate equation becomes grossly inaccurate at great distances.
In this way, it can be shown that an object with a spherically symmetric distribution of mass exerts the same gravitational attraction on external bodies as if all the object's mass were concentrated at a point at its center. [11] (This is not generally true for non-spherically symmetrical bodies.)
The mass of an object as measured in its own frame of reference is called its rest mass or invariant mass and is sometimes written . If an object moves with velocity v {\displaystyle \mathbf {v} } in some other reference frame, the quantity m = γ ( v ) m 0 {\displaystyle m=\gamma (\mathbf {v} )m_{0}} is often called the object's "relativistic ...
The term mass in special relativity usually refers to the rest mass of the object, which is the Newtonian mass as measured by an observer moving along with the object. The invariant mass is another name for the rest mass of single particles. The more general invariant mass (calculated with a more complicated formula) loosely corresponds to the ...
The momentum of the body is 1 kg·m·s −1. The moment of inertia is 1 kg·m 2. The angular momentum is 1 kg·m 2 ·s −1. The kinetic energy is 0.5 joule. The circumference of the orbit is 2 π (~6.283) metres. The period of the motion is 2 π seconds. The frequency is (2 π) −1 hertz.
For example, a 1 kg model airplane, traveling due north at 1 m/s in straight and level flight, has a momentum of 1 kg⋅m/s due north measured with reference to the ground. Many particles The momentum of a system of particles is the vector sum of their momenta.
In classical mechanics, the kinetic energy of a point object (an object so small that its mass can be assumed to exist at one point), or a non-rotating rigid body depends on the mass of the body as well as its speed. The kinetic energy is equal to 1/2 the product of the mass and the square of the speed. In formula form:
where μ is the reduced mass and r is the relative position r 2 − r 1 (with these written taking the center of mass as the origin, and thus both parallel to r) the rate of change of the angular momentum L equals the net torque N = = ˙ ˙ + ¨ , and using the property of the vector cross product that v × w = 0 for any vectors v and w ...