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The roots of the quadratic function y = 1 / 2 x 2 − 3x + 5 / 2 are the places where the graph intersects the x-axis, the values x = 1 and x = 5. They can be found via the quadratic formula. In elementary algebra, the quadratic formula is a closed-form expression describing the solutions of a quadratic equation.
However, the square of the distance (denoted d 2 or r 2), which has a paraboloid as its graph, is a smooth and analytic function. The dot product of a Euclidean vector with itself is equal to the square of its length: v⋅v = v 2. This is further generalised to quadratic forms in linear spaces via the inner product.
For the quadratic function y = x 2 − x − 2, the points where the graph crosses the x-axis, x = −1 and x = 2, are the solutions of the quadratic equation x 2 − x − 2 = 0. The process of completing the square makes use of the algebraic identity + + = (+), which represents a well-defined algorithm that can be used to solve any quadratic ...
Another geometric proof proceeds as follows: We start with the figure shown in the first diagram below, a large square with a smaller square removed from it. The side of the entire square is a, and the side of the small removed square is b. The area of the shaded region is . A cut is made, splitting the region into two rectangular pieces, as ...
Square number 16 as sum of gnomons. In mathematics, a square number or perfect square is an integer that is the square of an integer; [1] in other words, it is the product of some integer with itself. For example, 9 is a square number, since it equals 3 2 and can be written as 3 × 3.
In "twos in", binary quadratic forms are of the form ax 2 + 2bxy + cy 2, represented by the symmetric matrix This is the convention Gauss uses in Disquisitiones Arithmeticae. In "twos out", binary quadratic forms are of the form ax 2 + bxy + cy 2 , represented by the symmetric matrix ( a b / 2 b / 2 c ) . {\displaystyle {\begin{pmatrix}a&b/2\\b ...
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By writing + = (+) + = + we show that the sum of a positive number x and its reciprocal is always greater than or equal to 2. The square of a real expression is always greater than or equal to zero, which gives the stated bound; and here we achieve 2 just when x is 1, causing the square to vanish.